need help !! :))

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need help !! :))

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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  • phi
line 1 is ok. but line 2 is wrong in other words, (x-y)^2 is *not* x^2-y^2 (which is what they did) (x-y)^2 is x^2 +y^2 -2xy

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Other answers:

what am i supposed to d then? how do i solve it
  • phi
You did not post the question. I assume they want to know which line contains a mistake. If so, that would be line 2.
i have to find the mistake then solve it correctly
  • phi
ok. line 1 is technically not a mistake, but it is the wrong first step (line 2 is definitely a mistake) I would start over, with the original \[ x - \sqrt{17-4x}= 3 \] and put the square root on the right-hand side , like this: \[ x - \sqrt{17-4x} +\sqrt{17-4x} = 3 + \sqrt{17-4x} \] the left side simplifies \[ x= 3 + \sqrt{17-4x} \] now add -3 to both sides \[ x-3 = \sqrt{17-4x} \]
  • phi
now square both sides. on the left that means write (x-3)^2 on the right , what do you get after squaring ? any idea?
X^2-6X+9?
  • phi
yes, that is the left side. the right side is "easy" --- squaring gets rid of the square root side. can you write down the whole equation (both sides)?
X^2-6X+9=17-4X
  • phi
now add -17 to both sides and +4x to both sides
X^2-2X-8?
  • phi
you mean X^2-2X-8=0 remember it is an equation
A=1,B=-2,C=-8
  • phi
yes. you can use the quadratic formula (if they want you to) but you can factor this: notice -4* 2= -8 and -4+2= -2
OH YEAH
THATS IT? thanks so much!! :)
  • phi
(x-4)(x+2)= 0 either x-4=0 --> x=4 or x+2 =0 ---> x= -2 however, with these types of problems you have to check both solutions. sometimes you get an "extraneous" solution. So check both values in the original equation
-2 is false. thanks:)
  • phi
yes

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