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Unofficialllyy

  • one year ago

Can someone please help me with these 3 geometry questions? WILL FAN AND MEDAL!

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  1. Unofficialllyy
    • one year ago
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    The theme park company is building a scale model of the killer whale stadium main show tank for an investor's presentation. Each dimension will be made 6 times smaller to accommodate the mock-up in the presentation room. How many times smaller than the actual volume is the volume of the mock-up?

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  2. Unofficialllyy
    • one year ago
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    @phi

  3. Unofficialllyy
    • one year ago
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    @Vocaloid

  4. Vocaloid
    • one year ago
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    consider the relationship between dimensions and volume new length = (1/6)(old length) new width = (1/6)(old width) new depth = (1/6)(old depth) new volume = (1/6)*(1/6)*(1/6)*(old volume)

  5. Unofficialllyy
    • one year ago
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    So it's basically \[\frac{ 1 }{ 6 }^3*(359,189)\] 359,189 was the volume for the main show tank in the first part of the problem that I did.

  6. Vocaloid
    • one year ago
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    well, yeah, but it's not exactly what the question is asking it just wants you say compare the mockup volume and the actual volume "the mock-up volume is 6^3 times smaller than the actual volume" should suffice as an answer

  7. Unofficialllyy
    • one year ago
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    Oh I see. Okay here's the next part Using the information from #4, answer the following question by filling in the blank: The volume of the actual tank is ____% of the mock-up of the tank

  8. Unofficialllyy
    • one year ago
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    @sourwing

  9. Unofficialllyy
    • one year ago
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    @nincompoop

  10. Unofficialllyy
    • one year ago
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    @eyust707

  11. Unofficialllyy
    • one year ago
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    @jim_thompson5910 when you are online, could you check this out? :)

  12. Vocaloid
    • one year ago
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    "The volume of the actual tank is ____% of the mock-up of the tank" means 100*(actual volume)/(mock-up volume)

  13. Unofficialllyy
    • one year ago
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    So I need to find out the mock up volume. How would i do that?

  14. Vocaloid
    • one year ago
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    mock-up volume = (1/6)^3 * actual volume

  15. Unofficialllyy
    • one year ago
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    So like i had before so that would be 1662.91203704 ?

  16. Vocaloid
    • one year ago
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    yeah

  17. Unofficialllyy
    • one year ago
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    Then I would do \[100*\frac{ 359189 }{1662.91203704 }?\]

  18. Unofficialllyy
    • one year ago
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    Which is 21599.99999996

  19. Unofficialllyy
    • one year ago
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    @Vocaloid

  20. Vocaloid
    • one year ago
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    right, just make sure to round and add a percent sign at the end

  21. Unofficialllyy
    • one year ago
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    So that rounded would be 216%? Im not very good with rounding

  22. Unofficialllyy
    • one year ago
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    @Vocaloid

  23. Vocaloid
    • one year ago
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    21600%

  24. Unofficialllyy
    • one year ago
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    Okay this is the last part If you were to take a cross section parallel to the base of one of the holding tanks, how would you describe the shape?

  25. Vocaloid
    • one year ago
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    that's kind of a vague question, but the cross-section would be a rectangle, assuming we'r e just looking at the holding tank part

  26. Unofficialllyy
    • one year ago
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    What is a cross section?

  27. Vocaloid
    • one year ago
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    uh, it's a bit tough to explain but I'll try |dw:1437337323358:dw|

  28. Unofficialllyy
    • one year ago
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    So it's like cutting it in half?

  29. Vocaloid
    • one year ago
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    right, first you cut the tank, then you look at the tank from the top

  30. Vocaloid
    • one year ago
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    |dw:1437337461036:dw|

  31. Unofficialllyy
    • one year ago
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    So it says a cross section parallel, so if you cut the holding tanks in half parallel, would that make square or a rectangle?

  32. Vocaloid
    • one year ago
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    I would say rectangle, I guess a square is a possibility if you look at it from the other side

  33. Unofficialllyy
    • one year ago
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    Right, but I see why a rectangle. Thank you so much you were a huge help!

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