## amyna one year ago integration problem. I will draw it on the board. Please help!! I just don't understand how to get the other interval since its an absolute value problem- everything else i understand! THANKS

1. amyna

|dw:1437334447168:dw|

2. amyna

like what would the next interval be after pi and -pi over 2??

3. phi

cos is >=0 from -pi/2 to pi/2 so you can drop the | | for that inteval for pi/2 to pi cos is neg, so drop the | | and put in a -1 i.e. $\int_{\frac{\pi}{2}}^\pi - \cos x \ dx$

4. amistre64

|dw:1437337222962:dw| due to its symmetry, the interval in question is just 3, times the integral of cos(x) from 0 to pi/2