anonymous
  • anonymous
An expression is shown below: f(x) = –16x2 + 22x + 3 Part A: What are the x-intercepts of the graph of the f(x)? Show your work. (2 points) Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points) Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Australopithecus
anonymous
  • anonymous
campbell_st
anonymous
  • anonymous
@campbell_st

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More answers

anonymous
  • anonymous
@Keigh2015
anonymous
  • anonymous
can you help??
Keigh2015
  • Keigh2015
I am sorry this type of math is not my strong suit.
Keigh2015
  • Keigh2015
@misssunshinexxoxo can you help this person with their math?
anonymous
  • anonymous
its okay
anonymous
  • anonymous
Hi
misssunshinexxoxo
  • misssunshinexxoxo
This might help http://www.wolframalpha.com/input/?i=f%28x%29+%3D+%E2%80%9316x2+%2B+22x+%2B+3
campbell_st
  • campbell_st
well you need to factor the equation start with factoring out the negative... \[f(x) = -(16x^2 - 22x - 3)\] next multiply 16 and - 3 so -48 find the factors of -48 that add to -22 the larger factor is negative its a relatively easy pair to find...
anonymous
  • anonymous
i got −(8x+1)(2x−3)
campbell_st
  • campbell_st
that's correct so so to find the x-intercepts you need to solve 8x + 1 = 0 and 2x - 3 = 0 what values do you get...?
anonymous
  • anonymous
one minute
anonymous
  • anonymous
-1\8 and 3\2
anonymous
  • anonymous
thats what i got
campbell_st
  • campbell_st
ok so that's good now part B is it a maximum or minimum...?
campbell_st
  • campbell_st
you need to look at the sign of the leading coefficient
anonymous
  • anonymous
i have no clue @campbell_st
triciaal
  • triciaal
do you know what the coefficient is?
campbell_st
  • campbell_st
what is the leading term in the equation..?
anonymous
  • anonymous
-16 ?
campbell_st
  • campbell_st
so if its positive then you have a minimum, if its negative you have a maximum
anonymous
  • anonymous
oooh
campbell_st
  • campbell_st
great so which do you have, max or min...?
anonymous
  • anonymous
its both ??
anonymous
  • anonymous
-1\8 is max and and 3\2 in min >??
campbell_st
  • campbell_st
no if the leading coefficient is negative... do you have a max or min,,, it can't be both
campbell_st
  • campbell_st
here is the equation \[f(x) = -16x^2 + 22x + 3\] you said the leading coefficient is -16 that's correct... so if its a potive value you have a minimum if its negative you have a maximum so which do you choose
anonymous
  • anonymous
max
campbell_st
  • campbell_st
great... now the vertex
campbell_st
  • campbell_st
the easiest way is to find the line of symmetry do you know about that...?
anonymous
  • anonymous
no
triciaal
  • triciaal
|dw:1437335587120:dw|
anonymous
  • anonymous
ookay
campbell_st
  • campbell_st
ok the standard form of a quadratic is \[0 = ax^2 + bx + c\] the line of symmetry is found using \[x = \frac{-b}{2 \times a}\] in your question you have a = -16 and b = 22 you need to substitute the values into the equation to find x, the line of symmetry
anonymous
  • anonymous
1116
anonymous
  • anonymous
-11\16
anonymous
  • anonymous
@campbell_st
campbell_st
  • campbell_st
nearly x = 11/16 originally it was -22/-32 so you have the x value for the vertex, now substitute that value into the original equation to get the y value in the vertex...
anonymous
  • anonymous
umm
anonymous
  • anonymous
idk
campbell_st
  • campbell_st
so its \[f(11/16) = -16 \times (11/16)^2 + 22 \times (11/16) + 3\] you need to calculate this value...
anonymous
  • anonymous
idk
anonymous
  • anonymous
i hate this question, its so hard
anonymous
  • anonymous
@campbell_st
campbell_st
  • campbell_st
ok.... I have to go anyway.
anonymous
  • anonymous
okay

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