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anonymous

  • one year ago

An expression is shown below: f(x) = –16x2 + 22x + 3 Part A: What are the x-intercepts of the graph of the f(x)? Show your work. (2 points) Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points) Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)

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  1. anonymous
    • one year ago
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    @Australopithecus

  2. anonymous
    • one year ago
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    campbell_st

  3. anonymous
    • one year ago
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    @campbell_st

  4. anonymous
    • one year ago
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    @Keigh2015

  5. anonymous
    • one year ago
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    can you help??

  6. Keigh2015
    • one year ago
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    I am sorry this type of math is not my strong suit.

  7. Keigh2015
    • one year ago
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    @misssunshinexxoxo can you help this person with their math?

  8. anonymous
    • one year ago
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    its okay

  9. anonymous
    • one year ago
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    Hi

  10. misssunshinexxoxo
    • one year ago
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    This might help http://www.wolframalpha.com/input/?i=f%28x%29+%3D+%E2%80%9316x2+%2B+22x+%2B+3

  11. campbell_st
    • one year ago
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    well you need to factor the equation start with factoring out the negative... \[f(x) = -(16x^2 - 22x - 3)\] next multiply 16 and - 3 so -48 find the factors of -48 that add to -22 the larger factor is negative its a relatively easy pair to find...

  12. anonymous
    • one year ago
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    i got −(8x+1)(2x−3)

  13. campbell_st
    • one year ago
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    that's correct so so to find the x-intercepts you need to solve 8x + 1 = 0 and 2x - 3 = 0 what values do you get...?

  14. anonymous
    • one year ago
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    one minute

  15. anonymous
    • one year ago
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    -1\8 and 3\2

  16. anonymous
    • one year ago
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    thats what i got

  17. campbell_st
    • one year ago
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    ok so that's good now part B is it a maximum or minimum...?

  18. campbell_st
    • one year ago
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    you need to look at the sign of the leading coefficient

  19. anonymous
    • one year ago
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    i have no clue @campbell_st

  20. triciaal
    • one year ago
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    do you know what the coefficient is?

  21. campbell_st
    • one year ago
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    what is the leading term in the equation..?

  22. anonymous
    • one year ago
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    -16 ?

  23. campbell_st
    • one year ago
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    so if its positive then you have a minimum, if its negative you have a maximum

  24. anonymous
    • one year ago
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    oooh

  25. campbell_st
    • one year ago
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    great so which do you have, max or min...?

  26. anonymous
    • one year ago
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    its both ??

  27. anonymous
    • one year ago
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    -1\8 is max and and 3\2 in min >??

  28. campbell_st
    • one year ago
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    no if the leading coefficient is negative... do you have a max or min,,, it can't be both

  29. campbell_st
    • one year ago
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    here is the equation \[f(x) = -16x^2 + 22x + 3\] you said the leading coefficient is -16 that's correct... so if its a potive value you have a minimum if its negative you have a maximum so which do you choose

  30. anonymous
    • one year ago
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    max

  31. campbell_st
    • one year ago
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    great... now the vertex

  32. campbell_st
    • one year ago
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    the easiest way is to find the line of symmetry do you know about that...?

  33. anonymous
    • one year ago
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    no

  34. triciaal
    • one year ago
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    |dw:1437335587120:dw|

  35. anonymous
    • one year ago
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    ookay

  36. campbell_st
    • one year ago
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    ok the standard form of a quadratic is \[0 = ax^2 + bx + c\] the line of symmetry is found using \[x = \frac{-b}{2 \times a}\] in your question you have a = -16 and b = 22 you need to substitute the values into the equation to find x, the line of symmetry

  37. anonymous
    • one year ago
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    1116

  38. anonymous
    • one year ago
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    -11\16

  39. anonymous
    • one year ago
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    @campbell_st

  40. campbell_st
    • one year ago
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    nearly x = 11/16 originally it was -22/-32 so you have the x value for the vertex, now substitute that value into the original equation to get the y value in the vertex...

  41. anonymous
    • one year ago
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    umm

  42. anonymous
    • one year ago
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    idk

  43. campbell_st
    • one year ago
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    so its \[f(11/16) = -16 \times (11/16)^2 + 22 \times (11/16) + 3\] you need to calculate this value...

  44. anonymous
    • one year ago
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    idk

  45. anonymous
    • one year ago
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    i hate this question, its so hard

  46. anonymous
    • one year ago
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    @campbell_st

  47. campbell_st
    • one year ago
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    ok.... I have to go anyway.

  48. anonymous
    • one year ago
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    okay

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