A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

nincompoop

  • one year ago

establishing a proof for angle formed in a circle by intercepting chords

  • This Question is Closed
  1. misssunshinexxoxo
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Following.

  2. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    summoning the math gods and goddesses of OS

  3. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1437335161096:dw|

  4. misssunshinexxoxo
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @campbell_st

  5. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @kainui @waterineyes @Michele_Laino

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm pretty certain you can look up the proofs online

  7. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what is the statement which we have to demonstrate?

  8. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1437335345728:dw|

  9. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    vertical angles are congruent each other: |dw:1437335987601:dw|

  10. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    correct

  11. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    suppose we are given not the magnitudes of the chords but the angles of a and b how do we approach this?

  12. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    to figure out x or F

  13. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is F the intersection point? right?

  14. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    correct

  15. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry I don't know

  16. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think that we have to know at least one distance

  17. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for example the subsequent drawings have the same angles x |dw:1437337081389:dw|

  18. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the position of point F is not determined uniquely

  19. nincompoop
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can we establish that \(\large \frac{\bar {ED}}{\bar {GH}} = \frac{\bar {AF}}{\bar {FE}}\) and \(\bar {EF} \times \bar {FG} = \bar{DF} \times \bar {FH}\) then we can use some trig identities perhaps

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.