anonymous
  • anonymous
Suppose x is a normally distributed random variable with mean = 30 and standard deviation = 8. Find the value of the random variable, call it x(0), such that a. P(x>=x(0) = .5 b. P(x < x(0) = .025
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
and what do you have to work with?
amistre64
  • amistre64
and every stats student should know what the random variable for half of a normal distribution is ...
anonymous
  • anonymous
What do you mean by that? I believe that is all that is provided in the problem

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amistre64
  • amistre64
i am not taking your course, so I do not know what you have at your disposal to work with .... the information is beside the point.
amistre64
  • amistre64
ti83, or tables, or what?
anonymous
  • anonymous
Oh, I see. The problem and my teacher doesn't specify. I'm not sure what method to use, but I guess by regular and calclulator methods work
amistre64
  • amistre64
do you have a stats calculator?
anonymous
  • anonymous
Yea a ti-84
anonymous
  • anonymous
How would I show my work though?
amistre64
  • amistre64
can you find the distribution menu?
anonymous
  • anonymous
Yea I think so
amistre64
  • amistre64
well, you show your work by writing down the process you took to get the answer. i used this function and inputed this information, and got these results ...
amistre64
  • amistre64
you want what is called: INVNORM
anonymous
  • anonymous
ok i see invnorm
amistre64
  • amistre64
we will also prolly want to use the z formula, becuase all the invnorm function does is give us a zscore \[z=\frac{x-mean}{sd}\] since we are looking for x, we algebra it into \[x=mean+z(sd)\] given that z is the result of the invnorm function
amistre64
  • amistre64
a. P(x>=x(0)) = .5 invnorm(.5), hit enter b. P(x < x(0) = .025 invnorm(.025), hit enter
anonymous
  • anonymous
Ok I see, thank you
amistre64
  • amistre64
seeing that they give you the mean and sd x = 30 + 8z

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