Suppose x is a normally distributed random variable with mean = 30 and standard deviation = 8. Find the value of the random variable, call it x(0), such that a. P(x>=x(0) = .5 b. P(x < x(0) = .025

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Suppose x is a normally distributed random variable with mean = 30 and standard deviation = 8. Find the value of the random variable, call it x(0), such that a. P(x>=x(0) = .5 b. P(x < x(0) = .025

Mathematics
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and what do you have to work with?
and every stats student should know what the random variable for half of a normal distribution is ...
What do you mean by that? I believe that is all that is provided in the problem

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i am not taking your course, so I do not know what you have at your disposal to work with .... the information is beside the point.
ti83, or tables, or what?
Oh, I see. The problem and my teacher doesn't specify. I'm not sure what method to use, but I guess by regular and calclulator methods work
do you have a stats calculator?
Yea a ti-84
How would I show my work though?
can you find the distribution menu?
Yea I think so
well, you show your work by writing down the process you took to get the answer. i used this function and inputed this information, and got these results ...
you want what is called: INVNORM
ok i see invnorm
we will also prolly want to use the z formula, becuase all the invnorm function does is give us a zscore \[z=\frac{x-mean}{sd}\] since we are looking for x, we algebra it into \[x=mean+z(sd)\] given that z is the result of the invnorm function
a. P(x>=x(0)) = .5 invnorm(.5), hit enter b. P(x < x(0) = .025 invnorm(.025), hit enter
Ok I see, thank you
seeing that they give you the mean and sd x = 30 + 8z

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