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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1for the part of the function that is GREATER than 9, that is: \(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{+}}f(x)\)  for the part of the function that is SMALLER than 9, that is: \(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{}}f(x)\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1If these both limits are equal to each other, then whatever they are both equivalent to, is going to be your answer. If the limit from the left side and the limit from the right side are not equivalent, then your limit DNE

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1If you don't understand what I am saying I can redo the explanation better.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand what you are saying. I just need to know how to find the limit.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Just plug in 9 into each of the parts

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes, so your answer is 18

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1because the limit from both sides is equal to 18, that means that the twosided limit is also 18.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{}}f(x)=\lim_{x\rightarrow 9}(x+9)=9+9=18\) \(\displaystyle \LARGE\lim_{x\rightarrow 9^\color{red}{+}}f(x)=\lim_{x\rightarrow 9}(27x)=279=18\) Therefore, \(\displaystyle \LARGE\lim_{x\rightarrow 9}f(x)=18\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1the 27x corresponds to the limit from the right side, because it is for greaterthan9 values of x, and x+9 corresponds to the limit from the left side, because it is for smallerthan9 values of x.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1You are welcome...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That helps a lot. Thank you
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