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anonymous one year ago Factor. x2 + 7x + 12 A. (x – 12)(x – 1) B. (x – 6)(x – 2) C. (x + 3)(x + 4) D. (x – 3)(x – 4)

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1. DecentNabeel

$\mathrm{Factor}\:x^2+7x+12:\quad \left(x+3\right)\left(x+4\right)$

2. DecentNabeel

answer is option C

3. anonymous

you are a life saver

4. Nnesha

there are 3+ way to factor quadratic equations leading coefficient is on in this question so better to apply *headphone* method :D |dw:1437342979851:dw| multiply AC then find two number if you multiply them you should get product of AC and if you addo r subtract them you should get middle term

5. Nnesha

MR. Decent nabeel why so hurry eh ?

6. anonymous

lol

7. DecentNabeel

ok.. first break the expression into groups.. $=\left(4x+12\right)+\left(x^2+3x\right)$

8. Nnesha

enabling

9. anonymous

i appreciate the time your taking @Nnesha

10. anonymous

and you to @DecentNabeel

11. anonymous

(:

12. DecentNabeel

then $\mathrm{Factor\:out\:}4\mathrm{\:from\:}4x+12\mathrm{:\quad }4\left(x+3\right)$ $\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+3x\mathrm{:\quad }x\left(x+3\right)$ $=x\left(x+3\right)+4\left(x+3\right)$ factor out x+3 $=\left(x+4\right)\left(x+3\right)$

13. DecentNabeel

@Nnesha are you ok

14. anonymous

oooo ok thanks a who'll lot.

15. Nnesha

yes i'm thanks for asking.....

16. DecentNabeel

wellcoem :) @Nnesha

17. DecentNabeel

welcome @speartonion

18. anonymous

(:

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