A box of 15 parts contains 7 that are defective. A worker picks parts one at a time and attempts to install them. Find the probability of each outcome in​ (a) through​ (d). ​(a) The first two chosen are both good. nothing ​(Round to four decimal places as​ needed.)

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A box of 15 parts contains 7 that are defective. A worker picks parts one at a time and attempts to install them. Find the probability of each outcome in​ (a) through​ (d). ​(a) The first two chosen are both good. nothing ​(Round to four decimal places as​ needed.)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Please check your question, which probably contains typo(s) and incomplete. Cannot have 15 parts of which 77 are defective.
it a 7
P(two are good) \[=\frac{C _{2}^{8} }{C_{2}^{15} }\]=?

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30
ok im so lost 8/15
and 054
pl help me out
im so lost and dum
(a) Initially, there are 8 good out of 15, so probability of getting the first good one is 8/15. For the next one, there are only 7 good out of 14, so probability is 7/14. For this two step experiment, the probability of getting 2 good out of two is therefore (8/15)*(7/14)=4/15. Alternatively, you could use the formula by @Surjithayer

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