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VanillaAngelic

  • one year ago

A tank holds 50 gallons of a mixture of acid and water that is 30% acid. If 20 gallons of acid are added to the mixture, what is the percent of acid in the new mixture? Explain step by step please~

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  1. mathmate
    • one year ago
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    Hint: use \(C_1V_1 = C_2V_2+C_3V_3\) C2=0.30 V2=50 gal C3=1.0 V3=20 V1=50+20=70 Solve for C1.

  2. VanillaAngelic
    • one year ago
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    I still don't understand. Can you explain it in words please?

  3. VanillaAngelic
    • one year ago
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    @mathmate

  4. mathmate
    • one year ago
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    actually, the equation tells us how much pure acid there is before and after mixing. Once you have the volume of pure acid, we would divide by the volume 70 gal. to get the concentration.

  5. mathmate
    • one year ago
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    btw, CV gives the volume of the pure substance.

  6. amistre64
    • one year ago
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    parts per whole: 50(.30) + 20 is the part that is acid 50 + 20 is the whole lot of it

  7. VanillaAngelic
    • one year ago
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    Thank you!! @amistre64

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