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VanillaAngelic
 one year ago
A tank holds 50 gallons of a mixture of acid and water that is 30% acid. If 20 gallons of acid are added to the mixture, what is the percent of acid in the new mixture? Explain step by step please~
VanillaAngelic
 one year ago
A tank holds 50 gallons of a mixture of acid and water that is 30% acid. If 20 gallons of acid are added to the mixture, what is the percent of acid in the new mixture? Explain step by step please~

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mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Hint: use \(C_1V_1 = C_2V_2+C_3V_3\) C2=0.30 V2=50 gal C3=1.0 V3=20 V1=50+20=70 Solve for C1.

VanillaAngelic
 one year ago
Best ResponseYou've already chosen the best response.0I still don't understand. Can you explain it in words please?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1actually, the equation tells us how much pure acid there is before and after mixing. Once you have the volume of pure acid, we would divide by the volume 70 gal. to get the concentration.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1btw, CV gives the volume of the pure substance.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1parts per whole: 50(.30) + 20 is the part that is acid 50 + 20 is the whole lot of it

VanillaAngelic
 one year ago
Best ResponseYou've already chosen the best response.0Thank you!! @amistre64
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