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clara1223

  • one year ago

question in comments (logarithmic question)

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  1. clara1223
    • one year ago
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    \[\log _{4}(8-x)=3\] a) 56 b) -56 c) -73 d) 4 e) 72

  2. Nnesha
    • one year ago
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    convert log to exponential form example |dw:1437344474349:dw|

  3. clara1223
    • one year ago
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    @Nnesha thanks! got it.

  4. Nnesha
    • one year ago
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    are you sure?? let me know plz

  5. clara1223
    • one year ago
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    @Nnesha could you help me with some other logarithmic questions? #1: ln(x)+7=12 a) e^(12)-7 b)5^e c) e^(7)-12 d) 5 e) e^5 #2: \[\log _{2}(x)+\log _{2}(x-4)=\log _{2}(12)\] a) x=-2, x=6 b) x=0, x=4 c) x=2, x=-6 d) x=6 e) x=-2

  6. Nnesha
    • one year ago
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    alright okay so first one how would you cancel out ln?? do you know?

  7. clara1223
    • one year ago
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    no, can you explain it to me?

  8. Nnesha
    • one year ago
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    okay to cancel out ln you have to take e both side example \[\huge\rm \cancel{e^{\ln}} x = x\]

  9. Nnesha
    • one year ago
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    for example in this question i have to solve for x ln x = 3 so i would take ln both sides \[\huge\rm \color{red}{e}^{\ln} x= \color{ReD}{e}^3\] \[\huge\rm \cancel {\color{red}{e}^{\ln}} x= \color{ReD}{e}^3\] answer is x = e^3

  10. clara1223
    • one year ago
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    @Nnesha awesome! now could you help me with the last one?

  11. Nnesha
    • one year ago
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    you have to apply log property there

  12. clara1223
    • one year ago
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    what's log property?

  13. Nnesha
    • one year ago
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    mhm you can start log questions without knowing property! :)quotient rule\[\huge\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\huge\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication

  14. clara1223
    • one year ago
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    okay so once i have \[\log _{2}(x ^{2}-4x)=\log _{2}(12)\] what do I do?

  15. Nnesha
    • one year ago
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    nice so there are same bases both sides you can cancel each other ot \[\huge\rm \color{ReD}{log_b }x = \color{red}{\log_b} y \] \[\huge\rm\cancel{ \color{ReD}{log_b }}x = \cancel{\color{red}{\log_b}} y \] x=y

  16. clara1223
    • one year ago
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    @Nnesha got it! thanks so much for all the help!

  17. Nnesha
    • one year ago
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    my pleasure

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