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anonymous
 one year ago
question in comments (logarithmic question)
anonymous
 one year ago
question in comments (logarithmic question)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\log _{4}(8x)=3\] a) 56 b) 56 c) 73 d) 4 e) 72

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1convert log to exponential form example dw:1437344474349:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha thanks! got it.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1are you sure?? let me know plz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha could you help me with some other logarithmic questions? #1: ln(x)+7=12 a) e^(12)7 b)5^e c) e^(7)12 d) 5 e) e^5 #2: \[\log _{2}(x)+\log _{2}(x4)=\log _{2}(12)\] a) x=2, x=6 b) x=0, x=4 c) x=2, x=6 d) x=6 e) x=2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright okay so first one how would you cancel out ln?? do you know?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, can you explain it to me?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay to cancel out ln you have to take e both side example \[\huge\rm \cancel{e^{\ln}} x = x\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1for example in this question i have to solve for x ln x = 3 so i would take ln both sides \[\huge\rm \color{red}{e}^{\ln} x= \color{ReD}{e}^3\] \[\huge\rm \cancel {\color{red}{e}^{\ln}} x= \color{ReD}{e}^3\] answer is x = e^3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha awesome! now could you help me with the last one?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you have to apply log property there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what's log property?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1mhm you can start log questions without knowing property! :)quotient rule\[\huge\rm log_b y  \log_b x = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\huge\rm log_b x + \log_b y = \log_b( x \times y )\] addition > multiplication

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so once i have \[\log _{2}(x ^{2}4x)=\log _{2}(12)\] what do I do?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1nice so there are same bases both sides you can cancel each other ot \[\huge\rm \color{ReD}{log_b }x = \color{red}{\log_b} y \] \[\huge\rm\cancel{ \color{ReD}{log_b }}x = \cancel{\color{red}{\log_b}} y \] x=y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha got it! thanks so much for all the help!
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