Factor completely. 3x3 – 12x A.3x(x – 2)(x – 2) B.3x(x + 2)(x – 2) C.3(x + 2)(x – 2) D.3x(x – 4)

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Factor completely. 3x3 – 12x A.3x(x – 2)(x – 2) B.3x(x + 2)(x – 2) C.3(x + 2)(x – 2) D.3x(x – 4)

Mathematics
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3x³ - 12x, like this?
yes
\[\mathrm{Factor}\:3x^3-12x:\quad 3x\left(x+2\right)\left(x-2\right)\]

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ok, I will tell you that: 3x³ = 3x • x² 12x = 3x • 4
answer is option B
tanks bunches
thanks
\[\mathrm{Factor\:out\:}3x\] \[=3x\left(x^2-4\right)\] \[\mathrm{Factor}\:x^2-4:\quad \left(x+2\right)\left(x-2\right)\] \[=3x\left(x+2\right)\left(x-2\right)\]
are you ok @SolomonZelman
I know why I am here, to help people and not to give them answer. They maybe don't realize, but they won't have openstudy for their non-online tests. Also, I don't really see a single reason for why I shouldn't be ok.
take a chill pill
Just imagine yourself totally unprepared for an exam..... there is a way to prevent that, you know.
I won't further overwhelm on you though, I don't see how my talking right now can be any useful.... good luck, do well!

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