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anonymous

  • one year ago

Rewrite in simplest radical form 1 x −3 6 . Show each step of your process.

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  1. DecentNabeel
    • one year ago
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    \[\frac{\frac{1}{x}}{6^{-3}}=\frac{216}{x}\]

  2. DecentNabeel
    • one year ago
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    \[\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\] \[6^{-3}=\frac{1}{6^3}\] \[=\frac{\frac{1}{x}}{\frac{1}{6^3}}\] \[\mathrm{Divide\:fractions}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}\] \[=\frac{6^3}{x}\]

  3. DecentNabeel
    • one year ago
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    are you understand @boots_2000

  4. anonymous
    • one year ago
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    nope

  5. anonymous
    • one year ago
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    not at all

  6. anonymous
    • one year ago
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    1 over x raised 3 over 6 thats what the question was supposed to be

  7. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 1 }{ x^\frac{ 3 }{ 6 } }\] like this ?

  8. anonymous
    • one year ago
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    yes

  9. Nnesha
    • one year ago
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    alright you can reduce the fraction 3/6 =?

  10. anonymous
    • one year ago
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    1/2

  11. Nnesha
    • one year ago
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    yep right now you can change 1/2 root to radical \[\huge\rm x^\frac{ m }{ n } = \sqrt[n]{x^m}\]

  12. anonymous
    • one year ago
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    so my answer would be square root x of 1?

  13. Nnesha
    • one year ago
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    nope

  14. Nnesha
    • one year ago
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    \[\huge\rm x^\frac{ 1 }{ 2}=???\] let m = 1 and n =2 look at the exapmle i gave you

  15. Nnesha
    • one year ago
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    example*

  16. Nnesha
    • one year ago
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    yesright

  17. Nnesha
    • one year ago
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    sorry i didn't see word square so now you are not allowed to have radical at the denominator

  18. DecentNabeel
    • one year ago
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    \[\frac{1}{x^{\frac{3}{6}}}=\frac{1}{\sqrt{x}}\] \[\mathrm{Simplify}\:\frac{3}{6}:\quad \frac{1}{2}\] =1/x^(1/2) \[=\frac{1}{\sqrt{x}}\]

  19. anonymous
    • one year ago
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    \[\sqrt[2]{x ^{1}}\]

  20. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 1 }{ \sqrt{x}}\] multiply both the denominator and numerator by square root of x

  21. Nnesha
    • one year ago
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    don't forget the 1 at the numerator that stay there

  22. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 1 }{ \sqrt{x} } \times \frac{ \sqrt{x} }{ \sqrt{x} }\]

  23. anonymous
    • one year ago
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    \[1\div \sqrt[2]{x ^{1}}\]

  24. anonymous
    • one year ago
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    like that?

  25. Nnesha
    • one year ago
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    yes right now multiply both the top and bottom by the denominator (sqrt{{x}) = answer

  26. anonymous
    • one year ago
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    \[-\sqrt[2]{x ^{1}}\]

  27. Nnesha
    • one year ago
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    nope how did you get negative sign or is it typo ? ;)

  28. anonymous
    • one year ago
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    typo

  29. Nnesha
    • one year ago
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    btw radical sign mean square root so you don't have to write 2 .....

  30. anonymous
    • one year ago
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    sorry

  31. Nnesha
    • one year ago
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    \[\sqrt{ }\] <-- square root

  32. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 1 }{ \sqrt{x} } \times \frac{ \sqrt{x} }{ \sqrt{x} }\] multiply denominator by denominator and numerator y numerator

  33. anonymous
    • one year ago
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    so the answer is without the negative sign???

  34. anonymous
    • one year ago
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    so its just the suare root of x that we just put but withour the negative???

  35. Nnesha
    • one year ago
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    well there isn't any negative sign in the original question so it's pretty obvious :=) o^_^o

  36. Nnesha
    • one year ago
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    nope multiply

  37. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 1 }{ \sqrt{x} } \times \frac{ \sqrt{x} }{ \sqrt{x} }\] \[\frac{ 1 \times \sqrt{x} }{ \sqrt{x} \times \sqrt{x}}\]

  38. anonymous
    • one year ago
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    okay well im lost so imma just guess or not answer it

  39. Nnesha
    • one year ago
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    as you wish.. just one last step MULTIPLCATION! that's it done!

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