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itsmichelle29
 one year ago
Given the exponential function A(x) = P(1 + r)x, what value for r will make the function a growth function?
r = −2.1
r = −0.1
r = 0
r = 0.1
itsmichelle29
 one year ago
Given the exponential function A(x) = P(1 + r)x, what value for r will make the function a growth function? r = −2.1 r = −0.1 r = 0 r = 0.1

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1A(x)=P(1+r)\(^x\) like this ?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1so your rate is 1+r. Why? because: P(1+r)\(^1=\)P(1+r) P(1+r)\(^2=\)P(1+r)(1+r) P(1+r)\(^3=\)P(1+r)(1+r)(1+r) P(1+r)\(^4=\)P(1+r)(1+r)(1+r)(1+r) and so on....

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1so you always multiply times another 1+r if 1+r=1, then you multiply just times 1 and value doesn't change, if 1+r is less than 1, then your value is going to decrease (because if you multiply times 0.6 9/10 or any number smaller than 1) you make the value smaller. if 1+r is greater than 1, [only] then will your value be growing

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1So, for what value of r (the value of r in which answer choice), gives you a "1+r" that is GREATER than 1?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Yes, correct r=0.1 is the answer

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.1thank you so much medal and fan

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1no need, if you want to I won't refuse xD, but you aren;t required:)
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