itsmichelle29
  • itsmichelle29
Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression? 5 log 2x = log 27 2 log 5 = x log 27 x log 5 = 2 log 27 2x log 5 = log 27
Mathematics
schrodinger
  • schrodinger
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SolomonZelman
  • SolomonZelman
52\(^x\)=27 , like this, right?
itsmichelle29
  • itsmichelle29
no
itsmichelle29
  • itsmichelle29
5^2x=27

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SolomonZelman
  • SolomonZelman
5\(^{2x}\)=27 ?
SolomonZelman
  • SolomonZelman
take log of both sides.
SolomonZelman
  • SolomonZelman
and then apply the rule: log(c\(^w\))=w log(c)
SolomonZelman
  • SolomonZelman
5\(^{2x}\)=27 when you take the log of both sides, you get: log(5\(^{2x}\))=log(27) then apply the rule that I posted right before this, and you get?
itsmichelle29
  • itsmichelle29
i think
SolomonZelman
  • SolomonZelman
yes, that is right!
itsmichelle29
  • itsmichelle29
thank u
SolomonZelman
  • SolomonZelman
Alright!, Yw!

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