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itsmichelle29
 one year ago
Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression?
5 log 2x = log 27
2 log 5 = x log 27
x log 5 = 2 log 27
2x log 5 = log 27
itsmichelle29
 one year ago
Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression? 5 log 2x = log 27 2 log 5 = x log 27 x log 5 = 2 log 27 2x log 5 = log 27

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.152\(^x\)=27 , like this, right?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1take log of both sides.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1and then apply the rule: log(c\(^w\))=w log(c)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.15\(^{2x}\)=27 when you take the log of both sides, you get: log(5\(^{2x}\))=log(27) then apply the rule that I posted right before this, and you get?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes, that is right!
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