(FAN AND MEDAL) i really need help!!!

- anonymous

(FAN AND MEDAL) i really need help!!!

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- katieb

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- anonymous

@jdoe0001 @jim_thompson5910

- jdoe0001

answer is "blank"
since the question is "blank"
it follows it so, logically

- anonymous

wait let me writte the question

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## More answers

- anonymous

i need help on 3 and 4

##### 1 Attachment

- anonymous

@ganeshie8 @jdoe0001

- jim_thompson5910

when you plug x = 0 into the f(x) function, what result do you get?

- anonymous

x=1?

- anonymous

@jim_thompson5910 ???

- jim_thompson5910

f(x) = 3(4)^x
f(0) = 3(4)^0
f(0) = ???

- anonymous

f(0)=3?

- jim_thompson5910

yes, so (0,3) is one point on this curve

- jim_thompson5910

now plug in x = 1 and tell me what you get

- anonymous

x=1?

- jim_thompson5910

yeah instead of replacing x with 0, replace x with 1

- anonymous

(1, 2)

- anonymous

@jim_thompson5910

- jim_thompson5910

plug it into 3(4)^x

- anonymous

f(1) = 3* 4^1?

- anonymous

@jim_thompson5910

- jim_thompson5910

yeah, now evaluate what you just wrote down

- anonymous

f(1)=12?

- anonymous

@jim_thompson5910 ???

- jim_thompson5910

correct

- jim_thompson5910

if f(1) = 12, then what point is on this curve?

- anonymous

1?

- anonymous

(1, 2)?

- jim_thompson5910

(1,12) actually

- jim_thompson5910

the input is x = 1
the output of the function is y = 12
y is the same as f(x)

- jim_thompson5910

make sense?

- anonymous

yes ^_^

- jim_thompson5910

now plug in x = 2

- anonymous

f(1)= 3*4=12?

- jim_thompson5910

no just like before, instead of 1 plug in 2

- jim_thompson5910

plug 2 into 3(4)^x

- anonymous

10(2)^2?

- jim_thompson5910

idk how you're getting that

- anonymous

3(4)^2?

- anonymous

@jim_thompson5910 ???

- jim_thompson5910

much better

- jim_thompson5910

evaluate that

- anonymous

3*4^2?

- jim_thompson5910

what number is that expression equal to?

- anonymous

48

- jim_thompson5910

f(2) = 48 which means what point lies on the curve?

- anonymous

2?

- jim_thompson5910

|dw:1437354147178:dw|

- jim_thompson5910

|dw:1437354163352:dw|

- anonymous

48? ;/

- jim_thompson5910

I just posted it. Scroll up

- anonymous

so we done or what?

- jim_thompson5910

no

- jim_thompson5910

you have to find a bunch of points (3 or more). Then plot all of the points on the same xy grid. The last step is to draw a curve through all of the points

- anonymous

so the other point its (1, 2)

- anonymous

or (0, 2)

- jim_thompson5910

idk why you keep saying (1,2) when that's not correct

- jim_thompson5910

scroll back up to see what the true correct point should be

- anonymous

sorry, wait let me see

- anonymous

(0, 3)

- anonymous

idk ;/

- anonymous

its that right?

- jim_thompson5910

three points we found
(0,3)
(1,12)
(2,48)

- anonymous

so whats nexts?

- anonymous

or we done?

- jim_thompson5910

plot all of the points on the same xy grid. Then draw a curve through all of the points

- anonymous

and thats all? right

- jim_thompson5910

yeah

- anonymous

thank you!!!

- jim_thompson5910

no problem

- anonymous

can you help to plot the points, sorry

- anonymous

@jim_thompson5910 ??

- jim_thompson5910

you can use desmos to plot the points
https://www.desmos.com/calculator

- jim_thompson5910

or you can do it by hand on graph/grid paper

- anonymous

alright tank you so much!!!!! you're awesome! you think can you help me with number 4? please

- jim_thompson5910

you plug x = 3 into each function and determine the output

- jim_thompson5910

same with x = 10

- anonymous

thats for number 4?right?

- jim_thompson5910

yes

- jim_thompson5910

Amber: f(x) = 3(4)^x
Ben: g(x) = 2(3)^x
Carter: h(x) = 10(2)^x

- anonymous

and thats all

- anonymous

?

- jim_thompson5910

yes you need to plug x = 3 and x = 10 into each

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