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anonymous
 one year ago
Just want to make sure I'm on the right track.
NI3 + 2O > NO2 + 3I and 0.206 mols of oxygen react every minute in a 750.0mL vessel.
a. rate of oxygen consumption = 0.275 M/min ???
I also have to find rate of NI3 consumption and the rate of nitrogen dioxide and iodine production.
anonymous
 one year ago
Just want to make sure I'm on the right track. NI3 + 2O > NO2 + 3I and 0.206 mols of oxygen react every minute in a 750.0mL vessel. a. rate of oxygen consumption = 0.275 M/min ??? I also have to find rate of NI3 consumption and the rate of nitrogen dioxide and iodine production.

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cuanchi
 one year ago
Best ResponseYou've already chosen the best response.1The oxygen in the reaction is atomic oxygen O or molecular oxygen O2? I will said that if the oxygen react 0.206 moles and the container is 750mL you have less than a liter then that is not the concentration in Molarity, 1L x 0.206 mol/0.750 L= ???? Then: the rate of the reaction is Rate= Δ[O]/2Δt = Δ[NI3]/Δt =Δ[NO2]/Δt = Δ[I]/3Δt so you will have to divide the rate of consumption of oxygen by 2 to find the rate of consumption of NI3 and the rate of production of NO2. for the rate of production of I, you will have to multiply by 3 and divide by 2 the rate of oxygen
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