anonymous
  • anonymous
consider this systems of equations 2/3 x +3/5 y =12 5/2 y - 3x=6 the expression that gives the value of x is... the solution for the systems of equations...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
wolf1728
  • wolf1728
Do you know how to solve simultaneous equations?
anonymous
  • anonymous
no
wolf1728
  • wolf1728
A) 2/3 x +3/5 y =12 B) -3x +5/2 y =6 One way is to solve for x in one equation

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anonymous
  • anonymous
I don't get it
wolf1728
  • wolf1728
B) -3x = -5/2 y + 6 We divide both sides by -3 x = 5/6 y -2
anonymous
  • anonymous
options the expression that gives the value of x is... (5A/3)+(2B/5), (3A/5)-(5B/2), (5A/2)+(3B/5), (5A/3)-(2B/5), (3A/2) + (B/3)
UsukiDoll
  • UsukiDoll
mcfizzy STOP! What is that attachment?
anonymous
  • anonymous
the solution to the systems of equations is (1118/47, 396/47) (33/13, 50/13) (99/13, 150/13) (8,12)
anonymous
  • anonymous
@UsukiDoll what's wrong?
UsukiDoll
  • UsukiDoll
I've seen this poster (mcfizzy) posting an attachment that could be malicious. I've sent a report.
anonymous
  • anonymous
okay, I probably shouldn't click on the attachment then. I'll send a report too.
UsukiDoll
  • UsukiDoll
yeah.. under his profile all of his questions answered has spam with that attachment. everyone please report this.
anonymous
  • anonymous
I could use help with this problem, I'm still very confused
wolf1728
  • wolf1728
x = 99/13 y = 150/13
UsukiDoll
  • UsukiDoll
@wolf1728 is there to help. I have to warn everyone else about this issue as this is serious and against terms and conditions.
anonymous
  • anonymous
okay thank you
anonymous
  • anonymous
@wolf1728 I also need the expression that gives the value of x
wolf1728
  • wolf1728
Kaelyn - you do not know how to solve these so why do you need the expression for value of x ?
anonymous
  • anonymous
because the question asks me to find the expression that finds the value of x, I don't want you to give me the answer just help me find the right one
wolf1728
  • wolf1728
I think you should find someone else to help. I'm quitting for the moment.
anonymous
  • anonymous
okay thank you for your help
anonymous
  • anonymous
please help
anonymous
  • anonymous
May I try?
UsukiDoll
  • UsukiDoll
go for it @waterineyes as long as it's not a direct answer
anonymous
  • anonymous
go ahead @waterineyes
anonymous
  • anonymous
and @UsukiDoll I agree don't give the answer to me just help me find the answer myself
anonymous
  • anonymous
Okay, don't let our interaction stop anywhere, just reply if you know or not, just be with me...
anonymous
  • anonymous
okay
LynFran
  • LynFran
\[\frac{ 2 }{ 3 }x+\frac{ 3 }{ 4 }y=12\]\[\frac{ 5 }{ 2}y-3x=6\]frm equation 2,\[\frac{ 5 }{ 2 }y=6+3x\]\[y=\frac{ 2(6+3x) }{ 5 }\]now sub y=2(6+3x)/5 in eq 1 \[\frac{ 2 }{ 3 }x+\frac{ 3 }{ 4 }(\frac{ 2(6+3x) }{ 5 })=12\]simplify and solve for x we get \[\frac{ 2 }{ 3 }x+\frac{ 36+18x }{ 20 }=12\]\[\frac{ 40x +108+54x}{ 60 }=12\]\[\frac{ 94x+108 }{ 60 }=12\]multiply both side of the equation we get..\[94x+108=720\]\[94x=720-108\]\[x=612/94\]\[x=6.510638\]...so y =...\[y=\frac{ 2(6+3(6.510638)) }{ 5 }\]\[y=10.21276\]..
anonymous
  • anonymous
okay understanding so far
UsukiDoll
  • UsukiDoll
-_- *throws a water bottle @waterineyes
anonymous
  • anonymous
Both our equations are in fraction form, we should simplify them to make a good looking equation first... Do you know how to take LCM?
anonymous
  • anonymous
Hell, my net stopped working.. :(
anonymous
  • anonymous
Yes I know how to take LCM
anonymous
  • anonymous
Like in first equation, 15 is the LCM, so you can multiply whole equation by 15...
anonymous
  • anonymous
@LynFran I am afraid you are right everywhere, but you have taken wrong fraction in very first equation,, 3/5 is good, not 3/4.. if I am not blind then.. :P Your method is good.. :)
UsukiDoll
  • UsukiDoll
if we find our y and x, keep it in fraction form. ... decimals are a pain to deal with T_T
UsukiDoll
  • UsukiDoll
*throws a canteen at @waterineyes
anonymous
  • anonymous
Guys lets not throw things...
LynFran
  • LynFran
o i see im sleepy lol @waterineyes goodnight u guys
anonymous
  • anonymous
Goodnight @LynFran
anonymous
  • anonymous
\(10x + 9y = 180\) --- 1 This you got?
UsukiDoll
  • UsukiDoll
what is that ?
UsukiDoll
  • UsukiDoll
sigh....... the second equation is easier to deal with 2/3 x +3/5 y =12 5/2 y - 3x=6 \[\frac{2}{3}x+\frac{3}{5}y=12\] \[\frac{5}{2}y-3x=6\] so multiply 2 throughout the entire second equation \[\frac{5}{2}y-3x=6\]
anonymous
  • anonymous
And this way your second equation becomes: \(5y - 6x = 12\) --------- 2
UsukiDoll
  • UsukiDoll
uh huh
anonymous
  • anonymous
@Kaelyn78 are you getting how I formed these two equations?
anonymous
  • anonymous
yes I understand
UsukiDoll
  • UsukiDoll
10x + 9y = 180 5y-6x=12
anonymous
  • anonymous
Thanks.. Again and again I was going above to see these equations, as you are posting in between so things are going above..
anonymous
  • anonymous
you can write the second equation, other way round, x first and then y: \(10x + 9y = 180 \\ -6x + 5y = 12\)
anonymous
  • anonymous
\[[10x + 9y = 180 ] \times 6 = 60x + 45y = 108 \\ [-6x + 5y = 12 ] \times 10 = -60x + 50y = 120\]
anonymous
  • anonymous
I have multiplied the coefficient of x in second equation with first equation and same for second equation.. are you getting this step?
anonymous
  • anonymous
yes I understand
anonymous
  • anonymous
Now you just need to add those equations...
anonymous
  • anonymous
\[\cancel{60x} + 45y = 1080 \\ \cancel{-60x} + 50y = 120 \\ --------- \\95y = 2200\]
anonymous
  • anonymous
Sorry, that is 1080 and not 108...
anonymous
  • anonymous
okay
anonymous
  • anonymous
Getting previous step?
anonymous
  • anonymous
yes I'm getting it
anonymous
  • anonymous
Now find y, by dividing by 95 both the sides..
anonymous
  • anonymous
23?
anonymous
  • anonymous
Wait, I am just double checking it.. Let me take copy and pen too..
anonymous
  • anonymous
It is certainly a wrong...
anonymous
  • anonymous
9 multiplied by 6 is 54 not 45, just keep eyes on what I am doing, I can be wrong anywhere in writing digits. :P
anonymous
  • anonymous
After Multiplying 6 and 10 the equations you will get are: \(60x + 54y = 1080 \\ -60x + 50y = 120\) Form this you will get: \(104y = 2200\)
anonymous
  • anonymous
Kill me.....
anonymous
  • anonymous
1080 + 120 = 1200.. What has happened to me today.. :(
anonymous
  • anonymous
@waterineyes aw sorry I can't help with that
anonymous
  • anonymous
\(104y = 1200\) Now just find y by cancelling out the things..
anonymous
  • anonymous
if it's any consolation I would have gone certifiably insane trying to do this all by myself
anonymous
  • anonymous
thank you
anonymous
  • anonymous
\[y = \frac{1200}{104}\]
UsukiDoll
  • UsukiDoll
gotta reduce that fraction
anonymous
  • anonymous
Do not use calculator, just cancel it out with 8, you will get in fraction..
anonymous
  • anonymous
Now, put the fraction in any one of the equation above to find x...
anonymous
  • anonymous
Found value of y?
UsukiDoll
  • UsukiDoll
\[y=\frac{150}{13}\] 5y-6x=12 plug in y in this equation and solve for x
UsukiDoll
  • UsukiDoll
what are you talking about? I didn't post that.
UsukiDoll
  • UsukiDoll
\[5(\frac{150}{13})-6x=12\]
anonymous
  • anonymous
@Kaelyn78 what you got for y? You break the interaction?? :(
anonymous
  • anonymous
Okay, I gotta go now. If any doubt, Doll will tell you, or I will when I login next.. :) Solving these types of equations is really an easy task, just learn the concept, rest is a-jiffy work..
anonymous
  • anonymous
sorry fell asleep
anonymous
  • anonymous
I'm going to bed, thanks everyone, goodnight

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