anonymous
  • anonymous
Bobby is flying from city A to city C with a connection in city B. The probability his first flight arrives on time is 0.15. If the flight is on​ time, the probability that his luggage will make the connecting flight is 0.8​, but if the flight is​ delayed, the probability that the luggage will make it is only 0.55. In either​ case, Bobby makes the flight. Complete parts​ (a) and​ (b). a. What is the probability that Bobby's luggage is there to meet him in city​ C?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Bobby is flying from city A to city C with a connection in city B. The probability his first flight arrives on time is 0.15. If the flight is on​ time, the probability that his luggage will make the connecting flight is 0.8​, but if the flight is​ delayed, the probability that the luggage will make it is only 0.55. In either​ case, Bobby makes the flight. Complete parts​ (a) and​ (b). a. What is the probability that Bobby's luggage is there to meet him in city​ C?
triciaal
  • triciaal
|dw:1437365135548:dw|
triciaal
  • triciaal
one approach probability of flight on time and connect = 0.15*0.8 probability of delayed and connect = 0.85* 0.55

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triciaal
  • triciaal
add the probabilities
anonymous
  • anonymous
i mess up
triciaal
  • triciaal
did not see part (b)
anonymous
  • anonymous
(a) i mess up on
anonymous
  • anonymous
b. If Bobby'ss luggage is not there to meet him​, what is the probability that Bobby was late in arriving in city​ B?
anonymous
  • anonymous
Helppp
triciaal
  • triciaal
|dw:1437366014392:dw|
triciaal
  • triciaal
@freckles can you help with this?
anonymous
  • anonymous
0.5175
anonymous
  • anonymous
what did
freckles
  • freckles
someone correct me if I'm wrong I think it is \[P(lug)=P(lug|A)P(A)+P(lug| \text{ not } A)P(\text{ not } A)\] where we are given: \[P(lug|A)=.8 \\ P(A)=.15 \\ P(lug| \text{not } A)=.55\]

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