anonymous one year ago Bobby is flying from city A to city C with a connection in city B. The probability his first flight arrives on time is 0.15. If the flight is on​ time, the probability that his luggage will make the connecting flight is 0.8​, but if the flight is​ delayed, the probability that the luggage will make it is only 0.55. In either​ case, Bobby makes the flight. Complete parts​ (a) and​ (b). a. What is the probability that Bobby's luggage is there to meet him in city​ C?

1. anonymous

Bobby is flying from city A to city C with a connection in city B. The probability his first flight arrives on time is 0.15. If the flight is on​ time, the probability that his luggage will make the connecting flight is 0.8​, but if the flight is​ delayed, the probability that the luggage will make it is only 0.55. In either​ case, Bobby makes the flight. Complete parts​ (a) and​ (b). a. What is the probability that Bobby's luggage is there to meet him in city​ C?

2. triciaal

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3. triciaal

one approach probability of flight on time and connect = 0.15*0.8 probability of delayed and connect = 0.85* 0.55

4. triciaal

5. anonymous

i mess up

6. triciaal

did not see part (b)

7. anonymous

(a) i mess up on

8. anonymous

b. If Bobby'ss luggage is not there to meet him​, what is the probability that Bobby was late in arriving in city​ B?

9. anonymous

Helppp

10. triciaal

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11. triciaal

@freckles can you help with this?

12. anonymous

0.5175

13. anonymous

what did

14. freckles

someone correct me if I'm wrong I think it is $P(lug)=P(lug|A)P(A)+P(lug| \text{ not } A)P(\text{ not } A)$ where we are given: $P(lug|A)=.8 \\ P(A)=.15 \\ P(lug| \text{not } A)=.55$