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El_Arrow
 one year ago
don't understand this limit problem please help
El_Arrow
 one year ago
don't understand this limit problem please help

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El_Arrow
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand why she did that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0divide top and bottom by \(n^2\) so you can more easily see which terms dominate

El_Arrow
 one year ago
Best ResponseYou've already chosen the best response.0but if you do that in the bottom for example n^3/n^2 you get n not 1/n

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$\frac{3n^2+2n}{\sqrt{n^3+n^2+1}}\cdot\frac{1/n^2}{1/n^2}=\frac{3n^2+2n}{\sqrt{n^3+n^2+1}}\cdot\frac{1/n^2}{\sqrt{1/n^4}}=\frac{3+2/n}{\sqrt{1/n+1/n^2+1/n^4}}$$ so you can clearly

El_Arrow
 one year ago
Best ResponseYou've already chosen the best response.0oh so you square it when there is a square root?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually he did that..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh sorry, that was someone else you did that..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0see that in the limit as \(n\to\infty\), the square root tends to \(0\) while the top tends to \(3\); this tells us the terms 'blow up' as \(n\) grows larger and larger since the denominator gets ever smaller

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\frac{1}{x^2}} = \frac{1}{x} = \sqrt{\frac{1}{x^2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When you take x inside squares, it becomes \(x^2\)..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*square root brackets..

El_Arrow
 one year ago
Best ResponseYou've already chosen the best response.0i have one more question

El_Arrow
 one year ago
Best ResponseYou've already chosen the best response.0where did the 8 in this problem come from?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the distance between the vertex and focus (\(4\)) is equal to the distance between the vertex and directrix

El_Arrow
 one year ago
Best ResponseYou've already chosen the best response.0so you are add 4+4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437367323144:dw
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