A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

In Session 65 (Green's Theorem), there seems to be a mistake in the example (Using Green's Theorem). The double integral is calculated as 16*pi/3; shouldn't it be 8pi?

  • This Question is Open
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In the fourth equation in the example PDF, it says, \[\int\limits_{0}^{2\pi}\int\limits_{0}^{2}r^{2}rdrd \theta = \int\limits_{0}^{2\pi}\frac{ 8 }{ }\], but shouldn't it be \[\int\limits_{0}^{2\pi}4d \theta\] because the antiderivative of r^3 is r^4/4?

  2. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Apparently they overlooked the factor of r from dA = r dr dtheta and integrated r^2 to get r^3/3 and then 8/3 oops!

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.