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jessiegonzales
 one year ago
ALGEBRA 2
MEDAL!!!
12. Suppose a parabola has an axis of symmetry at x=7, a maximum height of 4 and also passes throughout the point (6,0). Write the equation of the parabola in vertex form.
jessiegonzales
 one year ago
ALGEBRA 2 MEDAL!!! 12. Suppose a parabola has an axis of symmetry at x=7, a maximum height of 4 and also passes throughout the point (6,0). Write the equation of the parabola in vertex form.

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jessiegonzales
 one year ago
Best ResponseYou've already chosen the best response.0i need step by step please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the axis of symmetry is 7 and the max height is four the vertex is (7, 4) and the parabola opens downward vertex form y = a(x  h)^2 + k [the "a" will be negative because the parabola opens downward] vertex is (h, k) y = a(x  (7))^2 + 4 y = a(x + 7)^2 + 4 solve for "a" by subbing in the given point (6, 0) 0 = a(6 + 7)^2 + 4 0 = a * 1 + 4 0 = a + 4 4 = a 4 = a so your equation is y = 4(x + 7)^2 + 4
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