anonymous
  • anonymous
find....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1437386418657:dw|
Astrophysics
  • Astrophysics
let u = cosx
anonymous
  • anonymous
ahh. I chose sin x. alright ´give me a moment to solve this.

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More answers

Astrophysics
  • Astrophysics
Naw, you will see why to, and np take your time
dan815
  • dan815
|dw:1437386882138:dw|
anonymous
  • anonymous
okey so \[\frac{ du }{ dx }=-\sin x\] \[\sin dx =-du\] \[\int\limits_{0}^{py/3} u^{3} *-1 du\] then you get
anonymous
  • anonymous
|dw:1437386925478:dw|
dan815
  • dan815
|dw:1437386942356:dw|
Astrophysics
  • Astrophysics
|dw:1437386975349:dw|
anonymous
  • anonymous
so my final answer was |dw:1437387078578:dw|
Astrophysics
  • Astrophysics
|dw:1437387056540:dw| dont forget to change the limits
Astrophysics
  • Astrophysics
When you're making a u sub make sure to change the limits as well
Astrophysics
  • Astrophysics
|dw:1437387169151:dw|
UsukiDoll
  • UsukiDoll
I would just sub that u back after we take the antiderivative so I won't have to change limits :P
Astrophysics
  • Astrophysics
Or yeah you can do it that way, it doesn't really matter
UsukiDoll
  • UsukiDoll
|dw:1437387304792:dw|
Astrophysics
  • Astrophysics
I just like doing it this way, it sometimes saves time haha
UsukiDoll
  • UsukiDoll
it's only half done @Xlegalize next you have to evaluate the integral
UsukiDoll
  • UsukiDoll
wahhhhhhhh I don't wanna sub old limits and get new ones ......... I rather just sub u back after antiderivative step and just evaluate so easier lezl
Astrophysics
  • Astrophysics
What ever works for you :P
anonymous
  • anonymous
ohh.. i thought it was done. how?
UsukiDoll
  • UsukiDoll
it was half done.. evaluating was missing at x = 0 cos(0) is 1
Astrophysics
  • Astrophysics
Oh, you have to use fundamental theorem of calculus still so |dw:1437387420691:dw|
UsukiDoll
  • UsukiDoll
|dw:1437387439915:dw|
Astrophysics
  • Astrophysics
Or pi/3* not negative :P
anonymous
  • anonymous
thats exactly what I did after I got the answer 0.265, the correct is 0.234
Astrophysics
  • Astrophysics
or is that suppose to be -pi/3?
UsukiDoll
  • UsukiDoll
|dw:1437387518604:dw|
Astrophysics
  • Astrophysics
or pi/3 idk
Astrophysics
  • Astrophysics
Yes you should get 15/64
Astrophysics
  • Astrophysics
So it is pi/3
UsukiDoll
  • UsukiDoll
pi/3 is 1.04 something.. that's not 0.2.34
Astrophysics
  • Astrophysics
Lol I have no clue what the intervals are
anonymous
  • anonymous
soo strange.. now I get the right answer. maybe it depends on how I plug it into the calc? tho it shouldnt. But I did like this. -cos(pi/3)^4/4+cos(0)^4/4
Astrophysics
  • Astrophysics
is that suppose to be pi/3 or -pi/3
anonymous
  • anonymous
srry -pi/3
Astrophysics
  • Astrophysics
Oh ok, let me just show you how to do it your way then
UsukiDoll
  • UsukiDoll
|dw:1437387699526:dw|
UsukiDoll
  • UsukiDoll
got em....
UsukiDoll
  • UsukiDoll
15/64 = 0.234375
UsukiDoll
  • UsukiDoll
I just evaluated...
Astrophysics
  • Astrophysics
|dw:1437387751936:dw| right?
UsukiDoll
  • UsukiDoll
yeah
Astrophysics
  • Astrophysics
|dw:1437387930922:dw| I'm doing it exactly the way you were doing/ would do it, just to make it clear.
Astrophysics
  • Astrophysics
|dw:1437388080251:dw| right?
UsukiDoll
  • UsukiDoll
hey waitttt.... we have -pi/3 meaning -1/2
Astrophysics
  • Astrophysics
It doesn't matter, cosx is an even function
anonymous
  • anonymous
yeah. thats where it started falling off.
Astrophysics
  • Astrophysics
|dw:1437388278120:dw|
ali2x2
  • ali2x2
a clif?
ali2x2
  • ali2x2
:P
Astrophysics
  • Astrophysics
It doesn't really matter in this question though as it's ^4 meaning it will be positive anyways but yes, cosx is an even function :O
ali2x2
  • ali2x2
:o
ali2x2
  • ali2x2
lol i saw that
Astrophysics
  • Astrophysics
Does that make sense though @Xlegalize
anonymous
  • anonymous
Alright, it has been done:D Thanks for all ur time and help and patience.
ali2x2
  • ali2x2
Nice work everyone now i rest me case

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