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anonymous
 one year ago
what is another expression for cos xsin x
anonymous
 one year ago
what is another expression for cos xsin x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0options A \[\sqrt{2} \cos \left( x+\frac{ \pi }{ 4 } \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2}\cos \left( x\frac{ \pi }{ 4} \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0C \[2\cos \left( x+\frac{ \pi }{ 4} \right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0D \[2\cos \left( x\frac{ \pi}{ 4 } \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: if I multiply and divide the left side by sqrt(2), I get this: \[\Large \sqrt 2 \left( {\frac{1}{{\sqrt 2 }}\cos x  \frac{1}{{\sqrt 2 }}\sin x} \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, please keep in mind that: \[\Large \frac{1}{{\sqrt 2 }} = \cos \left( {\frac{\pi }{4}} \right) = \sin \left( {\frac{\pi }{4}} \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: \[\Large \begin{gathered} \cos x  \sin x = \sqrt 2 \left( {\frac{1}{{\sqrt 2 }}\cos x  \frac{1}{{\sqrt 2 }}\sin x} \right) \hfill \\ \hfill \\ = \sqrt 2 \left( {\cos \left( {\frac{\pi }{4}} \right)\cos x  \sin \left( {\frac{\pi }{4}} \right)\sin x} \right) \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok,, 10nks.. but still stuck on how to simplify further

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can apply this identity: \[\Large \cos \left( {\alpha + \beta } \right) = \cos \alpha \cos \beta  \sin \alpha \sin \beta \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so that'll be \[\sqrt{2}(\cos(x+\frac{ \pi }{ 4}))\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the correct answer will be A

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! it is option A)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok,, thank u very much..
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