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\[f(x) = 3x^3-10x^2-81x+28 \] this?

if we need to find 0's then we need the rational root test.

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is the answer 7, -4, 1/3

but the last root lies somewhere between 0 and 1 and I think 1/3 is pretty close

answer choices
7,-4,1/3
7,-4,-1/3
7,4,1/3
7,4,-1/3

im pretty sure it is the last choice

did you test it out?

kind of

because there's a negative root.. and that number is not -1/3

so that knocks out two choices.

that means it is the third choice because after you test it out it gives you the third choice

no

negative root is x=-4

mhm ^

oops i think i know the answer for this question can you help me with another

yeah sure. you actually had the right answer 10 minutes ago XD

Which of the following is a polynomial with roots 5, 4i, and −4i

f(x) = x^3-5x^2+20x-16
f(x) = x^3-5x^2+16x-80
f(x)=x^3-20x^2+5x-16
f(x) = x^3-16x^2+80x-5

so plug 5 for each one

try let x = 5 for the second function

yeah for each one, but I think I've weeded it out
x=5 for the second function

i think i can take out the 2nd one and also the the first one

first one is nasty... x.x

so that is definitely eliminated

oh yeah... not to mention that the real root is x=1... not what we need.

the answer is the third one

umm are you sure?

im pretty sure

im feeling that my work shows that it is the answer

the last one

yes

thanks

you're welcome :)

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