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If y = A and y = B, then set A = B, solve for the X value
5 = 3x - 4
I got -1 ?
5 + 4 = 3x - 4 + 4 9 = 3x x = 3 y = 5 is already given
the answer that I have is 3,5 but it's wrong
the point (3,5) is where the two lines intersect
I got 239?
how is (3,5) wrong though? It does satisfy both equations
the y axis is right but the x axis isn't
are you trying to put this in a computer test
could be mymathlab stuff ?! that was horrible when I took Calculus II
you said you put 3,5 try (3,5)
I have in like that (3,5)
some sites are so super sensitive even though you have the right answer.
It's called Moodel
The y-coordinate is correct. Check the x again by graphing the system. thats the reply my teacher left
omg..... that means we have to use the graphing method
I would put a side note.... yo man solving for x helps too ...there's more than one method to solve a problem as long as it doesn't break math rules geez.
so I guess we have to graph y = 5 and y = 3x-4 -_-
so y = 5 means that our x is set at 0 so draw a horizontal line at (0,5)
and then for y = 3x-4 we have to let x be any number like x = 0,1,2,3 solve for y and plot points
that's about it.. if x = 3 there should be intersection... honestly... more than one method works... wow.
I'm just peeved at what your teacher wrote like... dude come on
my teacher isn't the best I'm serious
yeah it already shows smh
this is just a summer school class and I'm almost done I'm ahead of the class and she go upset about it
what was her reason to be upset at you though?
because 1 I was far ahead of the class , I came from a online home school so I'm usually ahead of my classes anyways
getting ahead is the best thing ever...even I got blasted for being ahead in my computer classes but I just didn't care about what my professors said.
but i'm going to public high school they want me to finish on pace with the rest, also is the answer 0,5
hmmm... if we're going to use the graphing method we have to graph y = 5 which is a horizontal line. Since x isn't given, it's already 0. so we have a horizontal line at (0,5) then for y=3x-4 we let x = 0,1,2,3... and solve for y to get points. we then use that information to graph until we find the point of intersection with is (3,5)
it is supposed to be (3,5) that's the point of intersection.... but since it's the graphing method instead of substitution method then we graph 2 lines.
did you graph y = 5 and y = 3x-4 ?
I had gotten -2
oh were you solving for y =3x-4 by letting x = 0,1,2,3 ?
I got -3 with zero
wait... for y = 3x-4 (just focus on that equation...nevermind the y =5) if x = 0 then y = -4...so we have one point (0,-4)
I'll just graph y = 5 and we can solve y =3x-4 together so we got one point already which is (0,-4) |dw:1437396951979:dw|
so is it -4 ?
yeah for y = 3x-4 x = 0 plug that in to the equation and we have y = -4
now let's try x = 1 plug in x = 1 into y =3x-4 y =3(1)-4 can you solve further?
i got -1
good so when x = 1, y = -1 another point (1,-1)|dw:1437397160711:dw|
for y = 3x-4 let x = 2 so plugging x = 2 into the equation y =3x-4 we have y=3(2)-4 and our y is ?
yes so (2,2) another point |dw:1437397289276:dw|
and we already solved when x = 3 |dw:1437397314401:dw|
so it would be (-3,5)?
that drawing sucks by the way x( it should be (3,5) the point of intersection which is the solution to those 2 equations
so it's (0,5)
(0,5) for y = 5 yes. It's just a horizontal line
thank you for helping me :D
oh wait XD sorry I read something wrong
we're still solving for x right ?
I don't think so.. when we did y =3x-4 we let x be any number we choose until we find the point which draws the line further to intersecting the other line. In this case when our x =3, our y = 5 since we have a horizontal line y =5 that point (3,5) from y =3x-4 crossed the horizontal line y = 5
as soon as we reach a certain x value that produces a point of intersection, we're done. If we have perpendicular lines (two lines that intersect) that means that there is one solution. 2 parallel lines means no solution.
so it is (0,5) I know i asked that a couple times I just wanted to make sure
is that for graphing y = 5 only? then yes it's (0,5) on the x-axis it's 0.. so x = 0 and y = 5 at point (0,5) the horizontal line is drawn
I have to submit the quiz so she can grade it yet again