simplifying the rational expression. State any excluded value 3x-6/x-2. I think it's A. 3; where x =2 (the equal has a line going through it) B. x C.6 where x =3 (also has a line going through the equal) One D.1 If i'm wrong let me know please explain the answer ^ ^

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simplifying the rational expression. State any excluded value 3x-6/x-2. I think it's A. 3; where x =2 (the equal has a line going through it) B. x C.6 where x =3 (also has a line going through the equal) One D.1 If i'm wrong let me know please explain the answer ^ ^

Mathematics
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this? \[\frac{3x-6}{x-2}\]
I hope factoring further isn't required because I can cancel out the x-2 if I take the three out so for this particular fraction we need to find an x that makes it undefined, so we need to exclude it . It's like solving x-2=0
Yeah It looks like that

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Okay, Can you help me solve it, i'm not good with math?
for x -2 = 0?
this feels like a double edge sword problem... if I factor further the denominator is wiped out
if I don't factor, then we can find an x value that makes the fraction undefined.
I don't have that option >~<
ahhhhhhh I found the problem :P one part is what makes that fraction undefined the other is to simplify XD
ok a two parter :P what makes x undefined? solve x-2 = 0
Not really sure 1?
x-2= 0 what do we need to do to have x by itself add, subtract, multiply, or divide
Get rid of add two to both sides?
yes so x =2 ... that's our restriction
\[\frac{3x-6}{x-2} \] now we just have to factor on the numerator . what number do they have in common? hint: it's the three times table 3 x 1 3 x 2
3?
yeah so we take the 3 out \[\frac{3(x-2)}{x-2}\]
then we can cancel out x-2
That leaves us with 3x?
close... just 3
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Alright Thanks. So that we make A right?
yup
Thanks again.

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