## anonymous one year ago Divide Anyone want to help me out? x^2 -4/x-8/x-2 A.(x-2)(x+2)/x -8 B.x-8/x+2 <-- This is wrong C.x-2/x-8 D.x+2/x-8 I think it is C i'm just being for sure I failed math the first time trying not to do that again. XD

1. Nnesha

is it $\huge\rm \frac{ \frac{ x^2 -4}{ x-8 } }{ x-2 }$

2. anonymous

Yes it is.

3. Nnesha

alright show your work plz

4. Nnesha

or explain how did you get C ?

5. anonymous

To be honest guess it XD

6. Nnesha

i knew it don't guess and btw it's too hard to pick the option whn there are 4!

7. anonymous

I Know but if you don't know how to solve it it's the next option.

8. Nnesha

$\huge\rm \frac{ \frac{ x^2 -4}{ x-8 } }{ x-2 }$ first of all change division the multiplication so multiply first fraction by the reciprocal of the bottom fraction example $\large\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d }}$ $\bf \frac{ a }{ b } \times \frac{ d }{ c }$

9. anonymous

4|dw:1437412031089:dw| Like this

10. Nnesha

what's that ?

11. anonymous

You said multiply by the reciprocal right.

12. Nnesha

yes reciprocal of the denominator

13. anonymous

So the -2 and the -8?

14. Nnesha

and btw you can't separate x and -8

15. Nnesha

nope

16. Nnesha

(x^2-4) don't separate

17. anonymous

Okay

18. anonymous

so x^2-4*x^2-4?

19. Nnesha

$\huge\rm \frac{ \frac{ x^2 -4}{ x-8 } }{\frac{ x-2}{1} }$ there is invisible one at the denominator of x-2

20. Nnesha

now multiply x^2-4/x-8 by the reciprocal of x-2/1

21. anonymous

I see why i guessed it :/ I don't understand this..

22. Nnesha

what is reciprocal of x-2 /1 ?