anonymous
  • anonymous
***WILL MEDAL AND FAN!!!*** A square with sides of https://suwannee.owschools.com/media/g_geo_2013/8/3rad2.gif is inscribed in a circle. What is the area of one of the sectors formed by the radii to the vertices of the square? a) 1.5pi b) 2.25pi c) 4.5pi
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@phi
anonymous
  • anonymous
|dw:1437403588550:dw|
anonymous
  • anonymous
so i think thats what the question is saying, and you need to find the area of the coloured in section. s is the side of the square which is 3sqrt(2). r is the radius of the circle, which is also equal to half of the diagonal line of the square. so first, we have to figure out the diagonal line of the square. that can be done by using pythagorian equation: (side1)^2+(side2)^2 = diagonal length^2

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phi
  • phi
|dw:1437403532240:dw|
anonymous
  • anonymous
Hence, (3sqrt(2))^2 + (3sqrt(2))^2 = d^2 Hence, d=6 (you can do the math following the equation above) so divide this by 2 in order to get the radius of the circle. therefore, r = 3 Next, you will notice that the coloured area we are looking for is only a quarter of the entire circle minus the area of a quarter of the entire square. So knowing that, first, you must the area of the circle using the equation: pi*r^2 = pi*(3)^2 = 9pi you need a quarter of that so divide it by 4 to get 9pi/4. Next, find the area of the square. length x width. So, 2*(3sqrt(2)) = 6sqrt(2) but similarly, you only need a quarter of that, so divide that by 4 to get 3sqrt(2)/2 Therefore, your final answer of the area of the coloured region will be the subtraction of the two areas: [(9pi/4)-(3sqrt(2)/2)] = (9pi-6sqrt(2))/4
anonymous
  • anonymous
Is this considered to be a Trigonometry question?
phi
  • phi
A sector is the shape of a piece of pie. The first step is to find the radius. The triangle is a 45-45-90 triangle, and you are given the hypotenuse
anonymous
  • anonymous
which is 3 and the sqare root of 2
phi
  • phi
the hypotenuse is \( 3 \sqrt{2} \) Do you remember (or have in your notes) how long is a side ? in a 45-45-90 triangle?
anonymous
  • anonymous
Honestly no I don't. That's been almost a year ago since I was learning about that
phi
  • phi
oh. math builds on itself and you end up using the old stuff... you can also use Kim's idea |dw:1437404053629:dw| and use the pythagorean theorem to find the diameter, and then find the radius
phi
  • phi
pythagoras is very famous a^2 + b^2 = c^2 where a and b are the legs, and c is the hypotenuse
anonymous
  • anonymous
I know I hear about the theorem every which way I turn! It's like the plague
phi
  • phi
It is amazing how often it shows up. (but I would not call it a plague) Look on the bright side, if you know it, you know a *lot*
anonymous
  • anonymous
Yeah
phi
  • phi
can you find the diameter?
anonymous
  • anonymous
Wouldn't that be the same as the hypotenuse?
phi
  • phi
yes, of the last figure I posted.
anonymous
  • anonymous
Sorry I left you hanging here. It was time to go
phi
  • phi
did you finish this or is it too late?
anonymous
  • anonymous
I didn't finish, but I really do need to though
anonymous
  • anonymous
Can anybody help me?
Loser66
  • Loser66
|dw:1437482709311:dw|
anonymous
  • anonymous
Finally somebody to help. Thanks!
Loser66
  • Loser66
hence the radius =3
Loser66
  • Loser66
That gives us the area of the WHOLE circle is 9pi
Loser66
  • Loser66
what you need? Because this guy is 1/4 of the circle |dw:1437482954457:dw|
Loser66
  • Loser66
|dw:1437483048616:dw|
phi
  • phi
fyi a sector is the two radius and the arc http://www.mathopenref.com/arcsector.html
anonymous
  • anonymous
Let me look. I'll be right back. Thanks!
anonymous
  • anonymous
@Loser66
anonymous
  • anonymous
@AaronAndyson
anonymous
  • anonymous
@dinosour1480
anonymous
  • anonymous
@jamesr
Nurali
  • Nurali
a² R² = ----- where a is the length of the side of the rectangle 2 In this case (3√2)² 9*2 R² = ------ = ----- = 9 2 2 so R = √9 => R = 3
Nurali
  • Nurali
Now radii to the vertices form an angle of 90° so we have to find the area of a sector of angle 90° angle 90° area of sector = -------- * πR² = ------ * 3² * π 360° 360° area of sector =2.25π
anonymous
  • anonymous
You made it sound so easy! Wow! Thanks!`

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