## anonymous one year ago can someone please me with this Part B The second part of the new coaster is a parabola. Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = ax2 + bx + c. Describe the direction of the parabola and determine the y-intercept and zeros. The safety inspector notes that Ray also needs to plan for a vertical ladder through the center of the coaster's parabolic shape for access to the coaster to perform safety repairs. Find the vertex and the equation for the axis of symmetry of the parabola, showing your work, so Ray can include it in his coaster plan. Create a graph of the polynomial function you created in Question 4.

1. anonymous

Please i would really appreciate the help!!

2. triciaal

in general when a is positive the parabola opens up and when a is negative the parabola opens down. the y-intercept the values of x when y = 0 the vertex is the maximum or minimum value of y when the value of x is the line of symmetry. vertex form for the equation of a parabola a(x-h)^2 + k where h = -b/2a the x-value and k is the corresponding y-value

3. anonymous

so for the first question what would be the best fit

4. triciaal

|dw:1437410792096:dw|

5. triciaal

|dw:1437410882917:dw|

6. anonymous

wait wait wait slow down a bit

7. anonymous

i dont think im onthe graphing part yet

8. anonymous

im still on the create a unique parabola part

9. triciaal

this is just general information for any parabola remember I don't have your specific equation so I cannot verify.

10. triciaal

take your time and incorporate the info I provided let me know when you need more help

11. anonymous

can i just get an example of a parabola with that equation

12. triciaal

13. triciaal

Create a unique parabola in the pattern f(x) = ax2 + bx + c. you should make one up

14. anonymous

thats the thing

15. anonymous

idk how

16. triciaal

a, b, c are your numbers

17. anonymous

@iGreen

18. triciaal

|dw:1437411641303:dw|

19. anonymous

thx

20. anonymous

so the direction ?

21. anonymous

do i use the first one u provided or the second one

22. anonymous

@triciaal

23. anonymous

can u help

24. anonymous

@triciaal

25. triciaal

26. triciaal

no do not use mine make up your own and follow my example that way you will learn more and "see' how to apply

27. anonymous

ok

28. anonymous

so how did u describe the direction of it

29. anonymous

how do u find that

30. triciaal

here my a is 2 positive graph open up when y = 0 solve for x = -3.69 and 0.69 total distance = around 4 1/2 of that around 2 so line of symmetry and x-value for vertex -3.69 + distance to line = -1.5 f(-1.5) = minimum = -9.5 vertex (-1.5, -9.5)

31. anonymous

so the direction is that it opens up right?

32. triciaal

|dw:1437413448755:dw|

33. triciaal

if a is positive the parabola opens up if a is negative the parabola opens down

34. triciaal

|dw:1437413580518:dw|

35. anonymous

so for the first question a parabola would be 2x^2 + 6x - 5.

36. anonymous

and the direction of it opens up

37. anonymous

is that correct?

38. anonymous

can i plz have the complete answer

39. triciaal

yes but use your own you might want to use something with whole numbers too I did not "check ahead" so the numbers here are not integers

40. anonymous

can i have the answer for the example u provided

41. anonymous

plz because this is my last question so i can complete my algebra 1 course these are my last questions can u just plz giv me the answer

42. triciaal

you need to slow down and read the responses I even gave you the picture of the graph for the example I used

43. anonymous

for the example u used i just want to know what the direction of it is and the y intercepts and zeros

44. anonymous

and ok

45. triciaal

the equation for the axis of symmetry x = -3/2

46. triciaal

LOOK AT THE GRAPH

47. anonymous

so it opens up?

48. anonymous

yes or no

49. anonymous

@triciaal

50. anonymous

thanks anyways

51. anonymous

@triciaal