can someone please me with this
Part B
The second part of the new coaster is a parabola.
Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = ax2 + bx + c. Describe the direction of the parabola and determine the y-intercept and zeros.
The safety inspector notes that Ray also needs to plan for a vertical ladder through the center of the coaster's parabolic shape for access to the coaster to perform safety repairs. Find the vertex and the equation for the axis of symmetry of the parabola, showing your work, so Ray can include it in his coaster plan.
Create a graph of the polynomial function you created in Question 4.

- anonymous

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- schrodinger

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- anonymous

Please i would really appreciate the help!!

- triciaal

in general when a is positive the parabola opens up and when a is negative the parabola opens down.
the y-intercept the values of x when y = 0
the vertex is the maximum or minimum value of y when the value of x is the line of symmetry.
vertex form for the equation of a parabola
a(x-h)^2 + k where h = -b/2a the x-value and k is the corresponding y-value

- anonymous

so for the first question what would be the best fit

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## More answers

- triciaal

|dw:1437410792096:dw|

- triciaal

|dw:1437410882917:dw|

- anonymous

wait wait wait slow down a bit

- anonymous

i dont think im onthe graphing part yet

- anonymous

im still on the create a unique parabola part

- triciaal

this is just general information for any parabola remember I don't have your specific equation so I cannot verify.

- triciaal

take your time and incorporate the info I provided let me know when you need more help

- anonymous

can i just get an example of a parabola with that equation

- triciaal

read your question
that is the equation for a parabola

- triciaal

Create a unique parabola in the pattern f(x) = ax2 + bx + c.
you should make one up

- anonymous

thats the thing

- anonymous

idk how

- triciaal

a, b, c are your numbers

- anonymous

@iGreen

- triciaal

|dw:1437411641303:dw|

- anonymous

thx

- anonymous

so the direction ?

- anonymous

do i use the first one u provided or the second one

- anonymous

@triciaal

- anonymous

can u help

- anonymous

@triciaal

- triciaal

##### 1 Attachment

- triciaal

no do not use mine
make up your own and follow my example that way you will learn more and "see' how to apply

- anonymous

ok

- anonymous

so how did u describe the direction of it

- anonymous

how do u find that

- triciaal

here my a is 2 positive graph open up
when y = 0 solve for x = -3.69 and 0.69
total distance = around 4 1/2 of that around 2 so line of symmetry and x-value for vertex -3.69 + distance to line = -1.5
f(-1.5) = minimum = -9.5 vertex (-1.5, -9.5)

- anonymous

so the direction is that it opens up right?

- triciaal

|dw:1437413448755:dw|

- triciaal

if a is positive the parabola opens up
if a is negative the parabola opens down

- triciaal

|dw:1437413580518:dw|

- anonymous

so for the first question a parabola would be 2x^2 + 6x - 5.

- anonymous

and the direction of it opens up

- anonymous

is that correct?

- anonymous

can i plz have the complete answer

- triciaal

yes but use your own
you might want to use something with whole numbers too
I did not "check ahead" so the numbers here are not integers

- anonymous

can i have the answer for the example u provided

- anonymous

plz because this is my last question so i can complete my algebra 1 course these are my last questions can u just plz giv me the answer

- triciaal

you need to slow down and read the responses I even gave you the picture of the graph
for the example I used

- anonymous

for the example u used i just want to know what the direction of it is and the y intercepts and zeros

- anonymous

and ok

- triciaal

the equation for the axis of symmetry x = -3/2

- triciaal

LOOK AT THE GRAPH

- anonymous

so it opens up?

- anonymous

yes or no

- anonymous

@triciaal

- anonymous

thanks anyways

- anonymous

@triciaal

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