A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Been stuck for hours
The function H(t) = −16t2 + 90t + 50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 28 + 48.8t, where g(t) is the height, in feet, of the object from the ground at time t seconds.
Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points)
Part B: Explain what the solution from Part A means in the context of the problem. (4 points)
anonymous
 one year ago
Been stuck for hours The function H(t) = −16t2 + 90t + 50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 28 + 48.8t, where g(t) is the height, in feet, of the object from the ground at time t seconds. Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points) Part B: Explain what the solution from Part A means in the context of the problem. (4 points)

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anybody got an idea? I'm basically just needing help on part A.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Start by evaluating both functions at t = 1, t = 2, t = 3, t = 4

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1How did you get 16?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1H(t) = −16t2 + 90t + 50 Let t = 1. What do you get for H(1) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just found it, idk how i got it, I guessed on it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like, i'm 100% lost on how I make these, I found some functions but idk how to graph them, can you explain?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1H(t) = −16t2 + 90t + 50 To find H(1) you replace t with 1, and you evaluate the expression. H(1) = 16(1)^2 + 90(1) + 50

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1H(1) = 16 + 90 + 50 = 124 Now you need H(2). Replace t with 2 in the H(t) function and evaluate the right side. H(2) = 16(2^2) + 90(2) + 50

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I evaluate it? Like how'd you get that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 is H(1) = 16 + 90 + 50 = 124, I need to solve for 2,3, and 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need to find 2,3,4 but how?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Evaluating an expression is just using arithmetic to calculate what it is equal to.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1For t = 2, you get H(2) = 16(2^2) + 90(2) + 50 What is the right side equal to?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0H(2) = 16(2v2) + 180 + 50?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1If I asked you what is 2 + 2, would you answer 2 + 2, or would you answer 4?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1good, keep going

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1H(2) =  64 + 230?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it'd be H(2) = 294, or since 64 is negative would it be H(2) = 166?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1So far we have: H(1) = 124 H(2) = 166 Now we still need H(3) and H(4) for function H(t) H(t) = −16t2 + 90t + 50 H(3) = 16(3)^2 + 90(3) + 50

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1No. First do 3^2

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1H(3) = 16(3)^2 + 90(3) + 50 H(3) = 16(9) + 90(3) + 50 Now do 16 * 9. You already have 90(3) + 50 = 320

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0144 + 270 + 50 right?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Correct. Now we need H(4) H(4) = 16(4)^2 + 90(4) + 50 Remember to start with 4^2 then multiply that by 16

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1I got 154 H(4) = 16(4)^2 + 90(4) + 50 = 256 + 360 + 50 =

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Ok. We have now function H(t) evaluated at t = 1, t = 2, t = 3, t = 4. Now we need to do the same for function g(t)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, what's the functions?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The g(t) function is simpler. Just multiply the number (1, 2, 3, 4) by 48.8, then add to 28. g(t) = 28 + 48.8t g(1) = 28 + 48.8(1) = g(1) = 28 + 48.8(2) = g(1) = 28 + 48.8(3) = g(1) = 28 + 48.8(4) =

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g(1) =76.8 g(2)=125.6 g(3)= 174.4 g(4)= 223.2

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Correct. Great job on function g(t). Now we place all values in a table like part A asks for. dw:1437421534524:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great, now that the graph's done what now? It says something about what 2 seconds match, or something

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Part A asks to look at the table and see between which two times the functions H and g have the same value.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437421963065:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Notice that at t = 3, H = 176 and g = 174.4, H is higher, but at t = 4, H = 154, and g = 223.2, g is higher. That means at some time between 3 and 4, the functions must have the same value.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I noticed, so that's the answer it requires?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The answer to part A is that the objects are at the same height sometime between 3 and 4 seconds.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Then the answer to part B is that the objects hit each other at that time between 3 and 4 seconds when their paths cross in the air.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much, I honestly would've never figured out how to work this problem. Thanks for the help :))

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You are welcome.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.