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anonymous

  • one year ago

Caden rolls two fair number cubes numbered from 1 to 6. He first defines the sample space, as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 6? 5 over 36 7 over 36 8 over 36 Points earned on this question: 0

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  1. anonymous
    • one year ago
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    @kropot72

  2. anonymous
    • one year ago
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    @kropot72

  3. kropot72
    • one year ago
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    You need to find the number of pairs that add up to 6. For example, in the first row there is one pair (1, 5). When you have found the number of pairs that add up to 6, divide that number of pairs by 36 (36 is the total number of possible outcomes), to find the required probability.

  4. anonymous
    • one year ago
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    would it be 5 over 36 @kropot72

  5. kropot72
    • one year ago
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    Yes, you are correct.

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