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anonymous
 one year ago
(FAN AND MEDAL)
anonymous
 one year ago
(FAN AND MEDAL)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The price of products may increase due to inflation and decrease due to depreciation. Derek is studying the change in the price of two products, A and B, over time. The price f(x), in dollars, of product A after x years is represented by the function below: f(x) = 72(1.25)x Part A: Is the price of product A increasing or decreasing and by what percentage per year? Justify your answer. (5 points) Part B: The table below shows the price f(t), in dollars, of product B after t years: t (number of years) 1 2 3 4 f(t) (price in dollars) 65 84.5 109.85 142.81 Which product recorded a greater percentage change in price over the previous year? Justify your answer. (5 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part I: You know that this function is DECREASING because 0.63, the number inside of the parenthesis, is LESS THAN THE NUMBER 1. I [think I] know the way to determine by what percentage it is decreasing. [I think] My teacher taught me that I have to subtract the number, in this case 0.63, from 1. So, 1  0.63 = 0.37. So it is decreasing by 0.37

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they are all changing by the same percentage: 43% less. And you can prove it by dividing year 2 to year 1 and dividing year 3 to year 2. Sorry for the inaccurate answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@campbell_st please help me! here nobody wanna help me! please help me

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1the function f(x) is like the compound interest formula it could be written as \[f(x) = 72 \times (1 + \frac{25}{100})^x\] the compound interest formula is \[A = P \times (1 + \frac{r}{100})^n\] where r is the growth rate as a percentage so when you compare it to your eqquation what do you think the growth rate r is..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need to solve that ?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1so for part A you can write (1.25) as (1 + 0.25) the + inside the brackets indicates its increasing and the amount of the increase is 0.25 written as a percentage

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer for part A: ITS the + inside the brackets indicates its increasing and the amount of the increase is 0.25 written as a percentage

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1part B find use the 1st 2 values \[%~increase = \frac{84.5  65}{65} \times 100\] then decide which percentage increase is greater... Product A (25%) or product B

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1the formula is \[increase = \frac{84.5  65}{65} \times 100\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well it should be a positive \[increase = \frac{19.5}{65} \times 100\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1that makes sense so whch has the larger increase product A (25%) or product b (30%)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer for part B: ITS: PRODUCT B HAS THE LARGER INCREASE?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much!!!! can you help me with 2 more or one more please!!!

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1sorry I can't I'm in Australia and about to go to class

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright its fine, thanks again!
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