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anonymous

  • one year ago

Let f(x) = 3x2 – x + 2 and g(x) = 5x2 – 1. Find f(g(x)). Show each step of your work.

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  1. anonymous
    • one year ago
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    Do you plug in g(x) in x2 and x?

  2. welshfella
    • one year ago
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    you get f(g(x)) by replacing each x is f(x) by g(x)

  3. welshfella
    • one year ago
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    * each x in

  4. anonymous
    • one year ago
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    ok I have my work on my paper could you do it too so I can compare and see If I did it right?

  5. anonymous
    • one year ago
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    ill medal and fan

  6. welshfella
    • one year ago
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    3(5x^2 - 1)^2 - (5x^1 - 1) + 2

  7. welshfella
    • one year ago
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    agreed?

  8. anonymous
    • one year ago
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    yep

  9. anonymous
    • one year ago
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    so far so good

  10. welshfella
    • one year ago
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    what do you get for the next line?

  11. anonymous
    • one year ago
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    75x^4-3-5x^2-1+2 that's what I get after I deal wit the parenthesis. Not sure if its correct though.

  12. welshfella
    • one year ago
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    no you deal with the (5x^2 - 1)^2 first this is a binomial = (5x^2 - 1)(5x^1 - 1) first you multiply th e second parentheses vy the 5 x^2 then by the -1 so its 25x^" - 5x^2 - 5x^2 + 1 = 25x^2 - 10x^2 + 1

  13. welshfella
    • one year ago
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    oh 'im making a lot of typos - its 3(25x^4 - 10x^2 + 1) - (5x^2 - 1) + 2 now be careful with - (5x^2 - 1) because you have to distribute the negative over the 5^2 - 1 and the -1 becomes + 1:- = 75x^4 - 30 x^2 + 3 - 5x^2 + 1 + 2 = 75x^4 - 35x^3 + 6

  14. anonymous
    • one year ago
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    Is that just the first part of the equation or is that the answer after you combine like terms and stuff

  15. welshfella
    • one year ago
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    - thats another typo!! its 35x^2 of course

  16. welshfella
    • one year ago
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    - thats the answer

  17. anonymous
    • one year ago
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    Oh I see what you did I multiplied wrong lol thanks for the help !

  18. welshfella
    • one year ago
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    I'm really tired so i'd better call it a day on OS today.

  19. welshfella
    • one year ago
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    yw

  20. welshfella
    • one year ago
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    when multiplying binomials its like this |dw:1437423013917:dw|

  21. welshfella
    • one year ago
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    4 multiplications

  22. anonymous
    • one year ago
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    ya foil I just didn't do it for some reason too im tired aswell lol

  23. welshfella
    • one year ago
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    good night

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