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anonymous
 one year ago
Given the functions f(x) = 6x + 11 and g(x) = x + 6, which of the following functions represents f[g(x)] correctly?
f[g(x)] = 6x + 47
f[g(x)] = 6x + 17
f[g(x)] = 6x2 + 47
f[g(x)] = 6x2 + 17
anonymous
 one year ago
Given the functions f(x) = 6x + 11 and g(x) = x + 6, which of the following functions represents f[g(x)] correctly? f[g(x)] = 6x + 47 f[g(x)] = 6x + 17 f[g(x)] = 6x2 + 47 f[g(x)] = 6x2 + 17

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can someone help explain this to me?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2f(g(x)) means that you have to put g(x) as the value of x in f(x)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1just replace x with x + 6 so f(x +6) = 5(x + 6) + 11 then just simplify

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1oops should be f(x + 6) = 6(x + 6) + 11 sorry for the typo

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2so u'll have  f(g(x)) = 6(g(x))+11 f(g(x))=6(x+6)+11 f(g(x))=6x+36+11 f(g(x))=6x+47

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, could you help me with some more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given the following functions f(x) and g(x), solve f[g(6)] and select the correct answer below: f(x) = 6x + 12 g(x) = x − 8 −96 0 24 48

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1just find the value of g(6) = 6  8 then substitute the answer into f(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so g(6) = 2 then I divide?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1then you substitute f(2) = 6(2) + 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you're a huge help lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with two more? @campbell_st
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