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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    #13 ONLY!

  2. freckles
    • one year ago
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    \[BE \cdot DE=CE \cdot AE \]

  3. freckles
    • one year ago
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    BE=2(EC) DE=3.5 so we have: \[2(EC) \cdot 3.5=EC \cdot AE \\ \text{ hmm this means we can actually find } AE \\ 2(3.5)=AE \text{ by dividing } EC \text{ on both sides } \\ AE=7'' \\ \text{ and we know } AC=12'' \\ \] but you can find CE now

  4. freckles
    • one year ago
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    but if not let me know if you are still stumped all the theorem I applied above it called the intersecting chord theorem

  5. moazzam07
    • one year ago
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    Freckels

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