derivative of sin(lnx)

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derivative of sin(lnx)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I know derivative of lnx is 1/x
Do you know your chain rule?
I think so! Just dont know where to start

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I would assume we do something like 1/u*du/dx
if you have \(y=f[g(x)]\) then: \(y'=f'[g(x)]g'(x)\)
Ill just get help on chegg
If you look at yours, you have sin(lnx) so, f(x) is sin(x) and g(x) is ln x.
So, what is the derivatve of sin(x)?

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