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anonymous

  • one year ago

will give medal and fan please help A carnival ride is in the shape of a wheel with a radius of 25 feet. The wheel has 20 cars attached to the center of the wheel. What is the central angle, arc length, and area of a sector between any two cars? Round answers to the nearest hundredth if applicable. You must show all work and calculations to receive credit.

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  1. jdoe0001
    • one year ago
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    so the wheel with 20 cars looks like http://www.uer.ca/forumpic/perspic/c2e2e83f7e21539f891d1e5e0723156f.jpg each car in each vertex, or corner keeping in mind that a circle has 360 degrees, how many degrees would there be between each vertex or corner, or in this case, each car?

  2. anonymous
    • one year ago
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    18

  3. jdoe0001
    • one year ago
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    yeap 360/20 is 18 so there's your central angle, 18 degrees :) now, we know the radius is 25 the central angle is 18 so, what's the arc's length? well \(\bf \textit{arc's length}=\cfrac{r\theta\pi }{180}\qquad \begin{cases} r=25\\ \theta=18 \end{cases}\implies \cfrac{25\cdot 18\cdot \pi }{180}\)

  4. jdoe0001
    • one year ago
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    to get the sector of that radius, with that angle \(\bf \textit{sector of a circle}=\cfrac{r^2\theta\pi }{360}\qquad \begin{cases} r=25\\ \theta=18 \end{cases}\implies \cfrac{25^2\cdot 18\cdot \pi }{360}\)

  5. anonymous
    • one year ago
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    okay so would the answer for arc length be 0.43?

  6. anonymous
    • one year ago
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    and the sector would it be 98.17?

  7. jdoe0001
    • one year ago
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    hmmm ahemm nope https://www.google.com/search?client=opera&q=25*18*pi/180&sourceid=opera&ie=utf-8&oe=utf-8&channel=suggest&gws_rd=ssl

  8. jdoe0001
    • one year ago
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    98.17 for the sector is correct

  9. anonymous
    • one year ago
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    thank you so much thats it right?

  10. jdoe0001
    • one year ago
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    yeap

  11. anonymous
    • one year ago
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    okay can you help me with another problem please

  12. jdoe0001
    • one year ago
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    sure, just post a new, more eyes, thus if I dunno, someone else may know

  13. anonymous
    • one year ago
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    okay i will

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