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anonymous

  • one year ago

a 10 foot ladder is leaning against a building. the ladder makes a 45 degree angle with the building. how far up the buildind does the ladder reach

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  1. anonymous
    • one year ago
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    |dw:1437436692596:dw|

  2. anonymous
    • one year ago
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    anyone help me

  3. anonymous
    • one year ago
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    @GEOMETRYHELP10011

  4. anonymous
    • one year ago
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    @geerky42 @HELP-ME-PLZ @mathmate

  5. calculusxy
    • one year ago
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  6. calculusxy
    • one year ago
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    Hopefully that screenshot might help you :)

  7. anonymous
    • one year ago
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    can you explain the problem to me

  8. anonymous
    • one year ago
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    @wil476003 @kropot72 @RosieF @youngBMW

  9. anonymous
    • one year ago
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    @GEOMETRYHELP10011

  10. calculusxy
    • one year ago
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    I honestly am not sure because I am a rising eighth grader. I need some time to understand the concept myself. If I have time, then I will try my best to help you.

  11. anonymous
    • one year ago
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    i dont know the answer stop tagging me

  12. calculusxy
    • one year ago
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    But all I do know is that you need to use either sine, cosine, or tangent to figure out the length of one side. Then you can use the Pythagorean Theorem from there: \[a^2 + b^2 = c^2\]

  13. phi
    • one year ago
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    This is a 45-45-90 triangle Have you studied this?

  14. phi
    • one year ago
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    |dw:1437437446661:dw|

  15. phi
    • one year ago
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    http://www.regentsprep.org/Regents/math/algtrig/ATT2/Ltri45.htm

  16. phi
    • one year ago
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    10 foot ladder is leaning the ladder forms the "hypotenuse"

  17. calculusxy
    • one year ago
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    sorry ur right.

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