anonymous one year ago There are 10 vehicles in a parking lot: 3 SUVs and 7 trucks. What is the probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks OR 3 SUVs and 4 trucks?

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1. kropot72

The required probability can be found as follows: $\large P((2SUV,5T)\ or\ (3SUV,4T))=\frac{3C2\times7C5}{10C7}+\frac{3C3\times7C4}{10C7}$