anonymous
  • anonymous
Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child? 4 over 12 plus 3 over 12 is equal to 7 over 12 4 over 12 plus 3 over 11 is equal to 80 over 132 4 over 12 multiplied by 3 over 12 is equal to 12 over 144 4 over 12 multiplied by 3 over 11 is equal to 12 over 132
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@misssunshinexxoxo
anonymous
  • anonymous
@cupcakerain
anonymous
  • anonymous
@Tabby_012 @night.soul45

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anonymous
  • anonymous
i will fan and medal
misssunshinexxoxo
  • misssunshinexxoxo
Which do you believe it is?
anonymous
  • anonymous
c or b @misssunshinexxoxo
anonymous
  • anonymous
@misssunshinexxoxo
anonymous
  • anonymous
@LynFran
kropot72
  • kropot72
The initial number of marbles is 12, of which 4 are blue. Therefore the probability of selecting a blue marble first is 4/12. Having selected a blue marble, there is a total of 11 marbles remaining of which 3 are yellow. Therefore the probability of a yellow marble being selected second is 3/11. The required probability is therefore given by \[\large \frac{4}{12}\times\frac{3}{11}\]
anonymous
  • anonymous
0.0909090909 @kropot72
anonymous
  • anonymous
i got it thanks
kropot72
  • kropot72
np.

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