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anonymous
 one year ago
Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child?
4 over 12 plus 3 over 12 is equal to 7 over 12
4 over 12 plus 3 over 11 is equal to 80 over 132
4 over 12 multiplied by 3 over 12 is equal to 12 over 144
4 over 12 multiplied by 3 over 11 is equal to 12 over 132
anonymous
 one year ago
Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child? 4 over 12 plus 3 over 12 is equal to 7 over 12 4 over 12 plus 3 over 11 is equal to 80 over 132 4 over 12 multiplied by 3 over 12 is equal to 12 over 144 4 over 12 multiplied by 3 over 11 is equal to 12 over 132

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Tabby_012 @night.soul45

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will fan and medal

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0Which do you believe it is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0c or b @misssunshinexxoxo

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1The initial number of marbles is 12, of which 4 are blue. Therefore the probability of selecting a blue marble first is 4/12. Having selected a blue marble, there is a total of 11 marbles remaining of which 3 are yellow. Therefore the probability of a yellow marble being selected second is 3/11. The required probability is therefore given by \[\large \frac{4}{12}\times\frac{3}{11}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00.0909090909 @kropot72
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