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anonymous

  • one year ago

Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child? 4 over 12 plus 3 over 12 is equal to 7 over 12 4 over 12 plus 3 over 11 is equal to 80 over 132 4 over 12 multiplied by 3 over 12 is equal to 12 over 144 4 over 12 multiplied by 3 over 11 is equal to 12 over 132

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  1. anonymous
    • one year ago
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    @misssunshinexxoxo

  2. anonymous
    • one year ago
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    @cupcakerain

  3. anonymous
    • one year ago
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    @Tabby_012 @night.soul45

  4. anonymous
    • one year ago
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    i will fan and medal

  5. misssunshinexxoxo
    • one year ago
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    Which do you believe it is?

  6. anonymous
    • one year ago
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    c or b @misssunshinexxoxo

  7. anonymous
    • one year ago
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    @misssunshinexxoxo

  8. anonymous
    • one year ago
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    @LynFran

  9. kropot72
    • one year ago
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    The initial number of marbles is 12, of which 4 are blue. Therefore the probability of selecting a blue marble first is 4/12. Having selected a blue marble, there is a total of 11 marbles remaining of which 3 are yellow. Therefore the probability of a yellow marble being selected second is 3/11. The required probability is therefore given by \[\large \frac{4}{12}\times\frac{3}{11}\]

  10. anonymous
    • one year ago
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    0.0909090909 @kropot72

  11. anonymous
    • one year ago
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    i got it thanks

  12. kropot72
    • one year ago
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    np.

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