anonymous
  • anonymous
find the center and radius of the circle x^2+2x-4y+6=0 will FAN and MEDAL
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathstudent55
  • mathstudent55
This is not a circle. Are you sure you copied the equation correctly? You need a y^2 term.
anonymous
  • anonymous
@mathstudent55 That is literally whats on my test. The answer options are: center (-1,2) radius :11 center (-1,2) radius: sq root of 11 center (1,-2) radius: 11 center (1,-2) radius sq root of 11
Mertsj
  • Mertsj
Well then let's work backwards from the answers and see which answer works.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Mertsj
  • Mertsj
\[(x+1)^2+(y-2)^2=11^2\]
Mertsj
  • Mertsj
\[x^2+2x+1+y^2-4y+4=121\]
Mertsj
  • Mertsj
\[x^2+2x+y^2-4y=116\]
Mertsj
  • Mertsj
Doesn't seem right, does it?
anonymous
  • anonymous
no
anonymous
  • anonymous
I am confused I kind of get what you did but I don't know how to continue it
Mertsj
  • Mertsj
The next choice has the same center but a different radius. But the radius should be sqrt116. So it doesn't seem to work either.
Mertsj
  • Mertsj
So try the third choice.
Mertsj
  • Mertsj
No. It couldn't be (x-1)^2 because that would be -2x
Mertsj
  • Mertsj
So of the choices given it has to be the first or the second one. And we know it isn't the first one.
Mertsj
  • Mertsj
Let's look at choice two more closely. I bet it will work.
anonymous
  • anonymous
ok! after could you help me with another one? it's the same but the equation is x^2+8x-6y+9=0 options are center (4,-3) radius sq root of 34 center (-4,3) radius sq root of 34 center (4,-3) radius 34 center (-4,3) radius 34
Mertsj
  • Mertsj
\[(x-1)^2+(y+2)^2=(\sqrt{11})^2\] \[x^2-2x+1+y^2+4y+4=11\] \[x^2-2x+y^2+4y+5=11\] \[x^2-2x+y^2+4y=6\]
Mertsj
  • Mertsj
The question is obviously flawed if you have posted it correctly but since it is multiple choice, b is the best shot you have.
anonymous
  • anonymous
thankyou! I've had so much trouble with that question!
Mertsj
  • Mertsj
Something is very wrong. Are you sure you posted the question EXACTLY as stated?
anonymous
  • anonymous
yes! I can post a screenshot if you'd like. I just don't know how to upload a picture
Mertsj
  • Mertsj
That would be good.
anonymous
  • anonymous
do you know how I can upload a pic?
Mertsj
  • Mertsj
All circles have x^2 and y^2 in their equations.
anonymous
  • anonymous
yeah that's what I thought but this question is really weird and theres a lot similiar to these on my test
Mertsj
  • Mertsj
I have never done that on this site.
anonymous
  • anonymous
I've seen other people do it...hmmm let me upload the pic to a site and then share the link
Mertsj
  • Mertsj
ok
anonymous
  • anonymous
http://s1252.photobucket.com/user/Beautiful_Rainbows/media/Screen%20Shot%202015-07-20%20at%207.46.30%20PM_zpssnamuhhc.png.html
anonymous
  • anonymous
[URL=http://s1252.photobucket.com/user/Beautiful_Rainbows/media/Screen%20Shot%202015-07-20%20at%207.46.30%20PM_zpssnamuhhc.png.html][IMG]http://i1252.photobucket.com/albums/hh562/Beautiful_Rainbows/Screen%20Shot%202015-07-20%20at%207.46.30%20PM_zpssnamuhhc.png[/IMG][/URL] try this link
Mertsj
  • Mertsj
It hasn't finished loading yet. I should warn you that my internet often goes down at 11 for some strange reason the Frontier can't seem to figure out. But the way the problem is posted, it has to be either choice b or .
anonymous
  • anonymous
Oh aw alright! What time is it rn where ur at? I chose answer b but I haven't submitted it yet
Mertsj
  • Mertsj
I see what you mean. For the second problem, let's try choice b. 10:52
mathstudent55
  • mathstudent55
The equation of a circle must have both the x-term and the y-term squared. The equation you were given is not a circle. I think they left out the y squared term.
anonymous
  • anonymous
aw man thats soon :( oh well...... wait for the second problem? so not the first one right? @mathstudent55 there are many questions like this on my test :(
Mertsj
  • Mertsj
\[(x+4)^2+(y-3)^2=(\sqrt{34})^2\] \[x^2+8x+16+y^2-6y+9=34\] \[x^2+8x+y^2-6y=9\]
anonymous
  • anonymous
so b for that one?
Mertsj
  • Mertsj
I would choose b and then I would point out to my teacher that these equations cannot be circles.
anonymous
  • anonymous
Oh okay! Thankyou so much for your time and help!
Mertsj
  • Mertsj
yw
anonymous
  • anonymous
do you know how to award a medal ? I'm not really sure how to haha
anonymous
  • anonymous
nvm I think i got it

Looking for something else?

Not the answer you are looking for? Search for more explanations.