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anonymous
 one year ago
find the center and radius of the circle x^2+2x4y+6=0
will FAN and MEDAL
anonymous
 one year ago
find the center and radius of the circle x^2+2x4y+6=0 will FAN and MEDAL

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0This is not a circle. Are you sure you copied the equation correctly? You need a y^2 term.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 That is literally whats on my test. The answer options are: center (1,2) radius :11 center (1,2) radius: sq root of 11 center (1,2) radius: 11 center (1,2) radius sq root of 11

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Well then let's work backwards from the answers and see which answer works.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2\[(x+1)^2+(y2)^2=11^2\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2\[x^2+2x+1+y^24y+4=121\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Doesn't seem right, does it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am confused I kind of get what you did but I don't know how to continue it

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2The next choice has the same center but a different radius. But the radius should be sqrt116. So it doesn't seem to work either.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2So try the third choice.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2No. It couldn't be (x1)^2 because that would be 2x

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2So of the choices given it has to be the first or the second one. And we know it isn't the first one.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Let's look at choice two more closely. I bet it will work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! after could you help me with another one? it's the same but the equation is x^2+8x6y+9=0 options are center (4,3) radius sq root of 34 center (4,3) radius sq root of 34 center (4,3) radius 34 center (4,3) radius 34

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2\[(x1)^2+(y+2)^2=(\sqrt{11})^2\] \[x^22x+1+y^2+4y+4=11\] \[x^22x+y^2+4y+5=11\] \[x^22x+y^2+4y=6\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2The question is obviously flawed if you have posted it correctly but since it is multiple choice, b is the best shot you have.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thankyou! I've had so much trouble with that question!

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Something is very wrong. Are you sure you posted the question EXACTLY as stated?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! I can post a screenshot if you'd like. I just don't know how to upload a picture

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know how I can upload a pic?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2All circles have x^2 and y^2 in their equations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that's what I thought but this question is really weird and theres a lot similiar to these on my test

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2I have never done that on this site.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've seen other people do it...hmmm let me upload the pic to a site and then share the link

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0[URL= http://s1252.photobucket.com/user/Beautiful_Rainbows/media/Screen%20Shot%2020150720%20at%207.46.30%20PM_zpssnamuhhc.png.html ][IMG] http://i1252.photobucket.com/albums/hh562/Beautiful_Rainbows/Screen%20Shot%2020150720%20at%207.46.30%20PM_zpssnamuhhc.png [/IMG][/URL] try this link

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2It hasn't finished loading yet. I should warn you that my internet often goes down at 11 for some strange reason the Frontier can't seem to figure out. But the way the problem is posted, it has to be either choice b or .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh aw alright! What time is it rn where ur at? I chose answer b but I haven't submitted it yet

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2I see what you mean. For the second problem, let's try choice b. 10:52

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The equation of a circle must have both the xterm and the yterm squared. The equation you were given is not a circle. I think they left out the y squared term.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0aw man thats soon :( oh well...... wait for the second problem? so not the first one right? @mathstudent55 there are many questions like this on my test :(

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2\[(x+4)^2+(y3)^2=(\sqrt{34})^2\] \[x^2+8x+16+y^26y+9=34\] \[x^2+8x+y^26y=9\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2I would choose b and then I would point out to my teacher that these equations cannot be circles.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay! Thankyou so much for your time and help!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to award a medal ? I'm not really sure how to haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nvm I think i got it
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