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This is not a circle. Are you sure you copied the equation correctly? You need a y^2 term.

Well then let's work backwards from the answers and see which answer works.

\[(x+1)^2+(y-2)^2=11^2\]

\[x^2+2x+1+y^2-4y+4=121\]

\[x^2+2x+y^2-4y=116\]

Doesn't seem right, does it?

no

I am confused
I kind of get what you did but I don't know how to continue it

So try the third choice.

No. It couldn't be (x-1)^2 because that would be -2x

Let's look at choice two more closely. I bet it will work.

thankyou! I've had so much trouble with that question!

Something is very wrong. Are you sure you posted the question EXACTLY as stated?

yes! I can post a screenshot if you'd like. I just don't know how to upload a picture

That would be good.

do you know how I can upload a pic?

All circles have x^2 and y^2 in their equations.

I have never done that on this site.

I've seen other people do it...hmmm let me upload the pic to a site and then share the link

ok

Oh aw alright! What time is it rn where ur at? I chose answer b but I haven't submitted it yet

I see what you mean. For the second problem, let's try choice b. 10:52

\[(x+4)^2+(y-3)^2=(\sqrt{34})^2\]
\[x^2+8x+16+y^2-6y+9=34\]
\[x^2+8x+y^2-6y=9\]

so b for that one?

I would choose b and then I would point out to my teacher that these equations cannot be circles.

Oh okay! Thankyou so much for your time and help!

yw

do you know how to award a medal ? I'm not really sure how to haha

nvm I think i got it