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anonymous
 one year ago
URGENT HElP
Where did I go wrong in my problem?!?!?
anonymous
 one year ago
URGENT HElP Where did I go wrong in my problem?!?!?

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so we have the quadratic equation \[x^2+6x+3\] using the discriminant formula \[ b^24ac \] we have \[(6)^24(1)(3) =3612 =24\] which is not a perfect square. I need to grab the latex for the quadratic equation brb

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[{x = \frac{{  6 \pm \sqrt {24} }}{{2}}} \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ok the problem lies in the square root... yes it is 24, but we can simplify that further.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so we need to find the smallest perfect square number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh I get it, so we can do √6 √4 which simplifies into 2√6 which would go away when divided by 2. right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also how do I explain why I chose this method?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[{x = \frac{{  6 \pm \sqrt {4 \cdot 6 } }}{{2}}} \rightarrow {x = \frac{{  6 \pm 2\sqrt {6} }}{{2}}}\] \[x = \frac{6}{2} \pm \frac{2\sqrt{6}}{2} \rightarrow 3 \pm \sqrt{6}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1First of all, we can't factor this equation. Using the discriminant formula, we obtain 24 and that's not a perfect square number. Therefore, we have to use the quadratic formula.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1Completing the square is useless because we are given a quadratic equation which is similar to the standard quadratic formula of \[ax^2+bx+c \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1I don't think we can do graphing either... our equation doesn't start with y =... that's kind of a generic excuse though.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thank you SO much
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