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anonymous

  • one year ago

Challenge! Ready? What are the values of x and y? http://assets.openstudy.com/updates/attachments/55ade084e4b071e6530cdc81-lollygirl217-1437459025179-as.jpg Hint...they both end in a fraction

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  1. anonymous
    • one year ago
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    Hint...they both end in a fraction

  2. anonymous
    • one year ago
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    So do you need help or what?

  3. anonymous
    • one year ago
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    We know that: \(\angle BAD \cong \angle CBD\)

  4. anonymous
    • one year ago
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    no.....it is a challenge

  5. anonymous
    • one year ago
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    Suppose the angle is \(\theta\). Then: \[ \sin(\theta) = \frac{y}{15+x} = \frac{8}{17} = \frac{x}{y} \]Also: \[ \cos(\theta) = \frac{17}{15+x} = \frac{15}{17} = \frac{8}{y} \]

  6. anonymous
    • one year ago
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    x= what y=what; that is how the answer is placed

  7. anonymous
    • one year ago
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    I'm not going to do someone else's homework

  8. anonymous
    • one year ago
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    Look on my profile...this is what I do.

  9. anonymous
    • one year ago
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    I just had a professor answer one of my challenges.

  10. anonymous
    • one year ago
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    anyone??

  11. welshfella
    • one year ago
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    you can apply the pythagoras theorem to large and smallest triangles (15 + x)^2 = 17^2 + y^2 y^2 + x/62 + 8^2

  12. welshfella
    • one year ago
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    * y^2 = x^2 + 8^2

  13. welshfella
    • one year ago
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    substituting y*2 = x^2 + 8^2 into the first equation (15 + x)^2 = 17^2 + x^2 + 8^2

  14. anonymous
    • one year ago
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    They both end in a fraction

  15. anonymous
    • one year ago
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    This is easy

  16. welshfella
    • one year ago
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    yea

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spraguer (Moderator)
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