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anonymous
 one year ago
in a sine wave:
v=100sin(200π*t+π/4)
10.7) Find the value of the greatest voltage rate of changee – you have already found
when this is and this value of t can be used in the expression for the rate of
change that you have also found (t=0.00125 or 0.00125)
10.8) Using integral calculus, calculate the RMS value of the voltage
anonymous
 one year ago
in a sine wave: v=100sin(200π*t+π/4) 10.7) Find the value of the greatest voltage rate of changee – you have already found when this is and this value of t can be used in the expression for the rate of change that you have also found (t=0.00125 or 0.00125) 10.8) Using integral calculus, calculate the RMS value of the voltage

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0equation edited...big hands and little keyboards don't mix well :(

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0hint 200(.00125)=.25=1/4 \[.00125\leq t \leq 0.00125\\.25\leq 200t \leq .25\\\frac{\pi}{4}\leq 200t\pi \leq \frac{\pi}{4}\\0\leq 200t\pi +\frac{\pi}{4}\leq \frac{\pi}{2}\]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437478833253:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought that the greatest voltage rate of change is simply where the line crosses the xaxis and is found by 2π*frequency*amplitude = The bit that's throwing me is having to use differential calculus to find it. Derivative of 100sin(200πt+4/π) = 20,000πcos(200πt+π/4). 2π*frequency*amplitude = 62831.8 but 20,000πcos(200πt+π/4) = 62808.2 surely these should equal the same? Also just realised that my original question didn't mention using differential calculus. Sorry about that.

Mrhoola
 one year ago
Best ResponseYou've already chosen the best response.110. 7) If you already know at what 't' the greatest rate of change occurs , then what I would do is take the derivative of the function and plug in +t. 10.8) Equation for RMS using an integral X_rms = \[\sqrt{1/T \int\limits_{0}^{T}(x)^2dt}\]
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