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Drewkatski
 one year ago
Hi I don't understand how to go about this question. thanks in advance for help.
The domains of these functions are the set of all positive real numbers, Find their ranges,
1. f(x)=2x+7
2. f(x)=x^21
Drewkatski
 one year ago
Hi I don't understand how to go about this question. thanks in advance for help. The domains of these functions are the set of all positive real numbers, Find their ranges, 1. f(x)=2x+7 2. f(x)=x^21

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alekos
 one year ago
Best ResponseYou've already chosen the best response.0the domain is all the possible x values which in this case is x>0 the range is all the possible y values

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0Note: number 2  what sign is a square number?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0 if x is real can a square number ever be negative?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0In any case x>0 as alekos has said so what does that make the range of values of x^2?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[x>0 \rightarrow 2x >0 \rightarrow 2x+7 >0+7\\x> 0 \rightarrow x^2 >0 \rightarrow x^21>01\]

Drewkatski
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I was afk, thanks to all for answering

Drewkatski
 one year ago
Best ResponseYou've already chosen the best response.0@amoodarya how do I apply this to one of the later questions: f(x) = (x+2)^21

phi
 one year ago
Best ResponseYou've already chosen the best response.0for f(x)=2x+7 if x>0 then f(x) will be bigger than 7 the range is y>7

alekos
 one year ago
Best ResponseYou've already chosen the best response.0with f(x) = (x+2)^2 1 just apply the same procedure x>0 x+2>2 and so on until you get f(x) > ......
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