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anonymous

  • one year ago

***PLEASE HELP! WILL MEDAL*** Express answer in exact form. Given a circle with an 8" radius, find the area of the smaller segment whose chord is 8" long and is there any way to put the answer in this format?: https://suwannee.owschools.com/media/g_geo_2013/8/q254_x.gif

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    @jamesr

  3. anonymous
    • one year ago
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    Since all sides are 8", they form an equilateral triangle. The area of the sector is pi*r^2*60/360 Subtract the area of the triangle, that leaves the sector. --------------- Sector = pi*64*/6 = 32pi/3 sq inches Area of triangle = 4*8*cos(30) = 16sqrt(3) Area of segment = (32pi/3) - 16sqrt(3)

  4. anonymous
    • one year ago
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    Thanks

  5. anonymous
    • one year ago
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    U WELCOME my b caps

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