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anonymous
 one year ago
Find all solutions in the interval [0, 2π).
2 sin2x = sin x
anonymous
 one year ago
Find all solutions in the interval [0, 2π). 2 sin2x = sin x

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0let sin =x to make it easy :D \[\huge\rm 2 x^2 = x\]set it equal to 0 and then take out common factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you elaborate more?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437488293143:dw alright so first step ) subtract x b oth sides

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0let me know what yo uget

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437488395098:dw x stay same at left side

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0now factor that equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0X(2^21) = 0 X(41) = 0 X(3)=0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0hmm it's x^2 not 2 to the 2 power

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0but yeah x is common factor so take it out \[\huge\rm x(2x1)\] now set x and (2x1) both equal to zero then solve for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x= 1/2 so i would have to look at the unit circle to find the ones with 1/2 as the sine value between 0 and 2π or 0 and 180

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0not between 0 180 0 360

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0at what point sin x = 1/2 and sin x = 0 too
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