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anonymous
 one year ago
WILL MEDAL AND FAN!!!
Express answer in exact form.
Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)
and is there any way to put the answer in this format?
https://suwannee.owschools.com/media/g_geo_2013/8/q255_x.gif
anonymous
 one year ago
WILL MEDAL AND FAN!!! Express answer in exact form. Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.) and is there any way to put the answer in this format? https://suwannee.owschools.com/media/g_geo_2013/8/q255_x.gif

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I appreciate you helpin'

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We know that the triangle formed by the two radii and the chord is an equilateral triangle, all angles are 60 degrees, which is 1/6 of 360 degrees : Find area inside the 60 degree arc 1/6*pi8^2 = 35.51 : Find the area of the equilateral triangle 1/2*8*SQRT8^24^2 = 27.71 sq/in : Find the area of the shape enclosed by the 60 degree arc and the chord 35.51  27.71 = 7.8 sq/in : Find the area of the larger segment pi*8^2  7.8 = 193.26 sq/inches NO PROBLEM damn caps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hehehe Lol! I know. It happens to me all the time. It's a real pain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ik rite and gtg ill message u when i get back around 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright. I appreciate the help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I still need a little help
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