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Help on what?
Two equations are shown: Equation 1: 3/4(x−12)=12 Equation 2: 3/4y−12=12 Solve each equation. Then, enter a number in each box to make this statement true. The value of x is: The value of y is:
The first thing you need to do is multiply each side by the denominator so you can get rid of it.|dw:1437491706702:dw|
ok makes sence
You can do the same with the second equation:|dw:1437491869576:dw|
ya cause they both have 3/4 that makes complete sence
Good. Did you get an answer?
hold on im doing it right now
so the nsubtract 12 from each side then u get|dw:1437492189668:dw|
You actually have to distribute the 12.|dw:1437492350008:dw|
oh ok then u can get rid of the other 12 after ok
but it wnt be a 12
then the 3 becomes easier to divide
What do you mean?
because my way you had to divide 3 by 4
When you did it, did you try and cancel out the 12s on the right side?
ya both 12s
That's where you went wrong, you can't cancel those out. It isn't subtraction throughout, you have to use the distributive property.|dw:1437492831341:dw|
i dont understand
The outside number has to be multiplied each term inside the parentheses. |dw:1437492979246:dw|
oh ok but dood sursly his is taking really long
its been half an hour
I am well aware. I have been trying to tell you to distribute. That is the only thing that is holding you up. If you would distribute, you would get the answers pretty quickly.
I actually already gave you the x value which was the harder of the two to get.
does y = 12
oh thats x nm